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777dan777 [17]
2 years ago
6

Every winter i fly home to Michigan. it takes 5 hours. what is my average speed?

Physics
2 answers:
Alisiya [41]2 years ago
8 0

It depends how far you travel.

If for instance you travel 1000 miles, then your speed is distance/time = 1000/5 = 200 mph

svetoff [14.1K]2 years ago
4 0

Answer:

first get a map and show how far you are from your original destination since the destination is not well identified where it is in Michigan so just get an approximate distance and then do the calculations

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if a charged plastic rod is brought near an uncharged metal rod on an insulating stand, an uncharged metal ball near the other e
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The phenomenon that is occurring is depicted in fig. Induction can be used to provide an explanation for this. As seen in Fig., when a negatively charged plastic rod is pushed close to a metal rod that is initially unaltered, the metal rod's left end picks up positive charges while the right end will pick up negative charges as a result of induction. when the empty metal ball is brought close to the metal rod's right end. The ball's near face subsequently develops a positive charge as a result of induction, and this positive charge attracts the rod since opposite charges are attracted to one another.

<h3>Define Induction?</h3>

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1 year ago
What would decrease the resistance of wires carrying an electric current
Murljashka [212]
I believe the answer is A. shorter wires


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3 years ago
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FEMA stands for Federal Emergency?
Nataliya [291]
FEMA stands for <span>Federal Emergency Management Agency</span>
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3 years ago
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Andrea's near point is 20.0 cm and her far point is 2.0 m. Her contact lenses are designed so that she can see objects that are
Shalnov [3]

Answer:

the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

Explanation:

Given the data in the question,

near point = 20 cm

far point = 2 m = 200 cm

Now, for an object that is infinitely far away, the image is at is its far point.

so using the following expression, we can determine the focal length

1/f = 1/i + 1/o

where f is the focal length, i is the image distance and o is the object distance.

here, far point i = 2 m = 200 cm  and v is ∞

so we substitute

1/f = 1/(-200 cm)  +  1/∞

f = -200 cm

Also, for object at its closest point, the image appear at near point,

so

1/f = 1/i + 1/o

we make o the subject of formula

o = ( i × f ) / ( i - f )

given that near point i = 20 cm

we substitute

o = ( -20 × -200 ) / ( -20 - (-200) )

o = 4000 / 180

o = 22.2 cm

Therefore, the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

4 0
3 years ago
A 23 kg body is moving through space in the positive direction of an x axis with a speed of 130 m/s when, due to an internal exp
babymother [125]

Answer:

a) Vx = 1088m/s

b) Vy = -162.93m/s

c) 5246745J

Explanation:

Mass of unbroken body = 23kg

Its velocity along +ve X-axis = 130m/s

Mass of first broken body, m1= 9.4kg

Its velocity along +ve X-axis = 130m/s

Nass of 2nd broken body, m2 = 6.1kg

Its velocity long-lived X - axis = -550m/s

Mass of 3rd broken body = ?

m3 = (23 - 9.4 - 6.1)kg

m3 = 7.5kg

Let velocity along the x-axis = Vx

Let the velocity along the x-axis = Vy

Applying law of conservation of momentum along x-axis

a) m1×0 + m2×(-550) + m3×(Vx) =M × 130

9.4 × 0 + 6.1× (-550) + 7.5(Vx) = 23 ×130

0 + (-5170) + 7.5Vx = 2990

2990 + 5170 = 7.5Vx

8160 = 7.5Vx

Vx = 8160/7.5

Vx = 1088m/s

b) Aplying conservation of momentum along the x-axis

(m1×130) + (m2 × 0) + (m3× Vy) = 0

(9.4 × 130) + (6.1 ×550) + 7.5Vy = 0

1222 + 0 + 7.5Vy = 0

1222 = -7.5Vy

Vy = 1222/(-7.5)

Vy = -262.93m/s

c) The energy released or change in KE is given by:

1/2[(m1v1^2) + (m2v2^2) +(m3Vx^2) ]= MV^2

Change in KE = 1/2[ 9.4× 130^2 + 6.1 × 550^2 + 7.5 × 1088^2 ] - 1/2(23 × 130^2)

Change in KE = 1/2[158860 + 1845250 + 8878080] - 1/2[388700]

Change in KE = 5441095 - 194350

Change in KE = 5246745J

4 0
3 years ago
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