The osmium with a density of 22.6g/cm3 has a volume in cm3 of 0.965 cm3
The density formula and the procedure we will use is:
ρ = m/v
Where:
- v= volume
- ρ= density
- m= mass
Information about the problem:
Applying the density formula and isolating the volume (v), we get:
ρ = m/v
v = m / ρ
v = 21.8 g / 22.6g/cm3
v = 0.965 cm3
<h3>What is density?</h3>
It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
Learn more about density in: brainly.com/question/1354972
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Answer: 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
Explanation:
To calculate the moles :
According to stoichiometry :
As 2 moles of octane give = 16 moles of
Thus 3.07 moles of octane will give = of
Mass of
Thus 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
Hey there!
Molar mass NaCl = 58.44 g/mol
number of moles:
n = m / mm
n = 15.0 / 58.44
n = 0.2566 moles of NaCl
Volume in Kg :
50.0 g / 1000 => 0.05 Kg
Therefore :
Molality = moles of solute / volume
Molatity = 0.2566 / 0.05
Molality = 5.132 mol/kg