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Reil [10]
3 years ago
10

What do producers do with carbon? (little information needed)

Biology
2 answers:
Virty [35]3 years ago
6 0
Producers convert water, carbon dioxide, and other minerals to create photosynthesis
alekssr [168]3 years ago
4 0

Answer:

They transform it into oxygen through cellular respiration

Explanation:

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Which group of organisms would Schleiden have been most likely to study?
madam [21]

I believe the answer is flower, pine tree, or cactus because he concluded plants are made of cells:)

6 0
3 years ago
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PLS HELP, I WILL MARK BRAINLIEST I NEED HELP​
kirill [66]

Answer: 0%

Explanation: white eyes is rr and red eyes is RR and if it had Rr it would still be red.

So the boxes filled in are rr and RR and offspring are Rr Rr Rr Rr which means there is no chance of a female offspring with white eyes (I think)

6 0
3 years ago
Suppose that you have some rod-shaped bacteria, and each bacterium is 3 micrometers long. If the bacteria were arranged end to e
Amiraneli [1.4K]

Answer:

Number of bacteria required = 20000

Explanation:

Given -

Size of each bacterium = 3 micrometers long

These bacteria are arranged end to end.

The size of chain to be formed is equal to 6 centimetres

Let us say that in forming a chain of 6 centimetres nearly X number of individual bacterium are required.

hence, number of bacterium required to form 6 centimetres  chain can be represented as

X = \frac{6 * 10000}{3} \\X = 20000

Number of bacteria required = 20000

7 0
3 years ago
A loopful of bacteria containing 1000 bacterial cells is inoculated into a nutrient broth and incubated. After a negligible lag
Black_prince [1.1K]

Answer:

<h2>a.  1000 X 2^8</h2>

Explanation:

As given;

Initial population of bacteria= 1000;

Log phase growth is exponential phase, period in which bacteria gets double.

Generation time= 15 minutes;

it means, bacteria get double in every 15 minute,

so after 2 hours, bacteria will have 8 generation times;

so the final generation of bacteria is =1000 X 2^8.

Final bacterial generation after two hours = 256,000(1000 X 2^8)

5 0
3 years ago
The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61
erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately<u> 6890 years.</u>

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

<u>Available data</u>:

  • The half-life of C14 is 5730 years
  • Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g
  • C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5730 years
  • T₀ = Time when the organism was alive
  • T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

<u>λ = 0.0001209</u>

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 =<u> - 0.833</u>

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ =  6889.99 ≅ <u>6890 years</u>

The bones are approximately<u> 6890 years.</u>

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0
3 years ago
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