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mr Goodwill [35]
3 years ago
15

What are the coordinates of the midpoint between the points (-6, -2) and (-2,-5)?

Mathematics
2 answers:
Soloha48 [4]3 years ago
7 0

B, -4, -7/2 is the midpoint

Tpy6a [65]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Mid-point = (x1+x2)/2 , (y1+y2)/2

= (-6-2)/2 , (-2-5)/2

= -8/2 , -7/2

= -4 , -7/2

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We will look at the process of solving literal equations for a particular variable ( x ).

A literal equation is usually categorized by a myraid of constants that are crucial to the process which is being modeled. We solve such equation in terms of a controlling variable ( that we can choose to alter our process ).

For the following literal equations ( x ) will be the subject of variability.

3\cdot(bx\text{ - 2ab ) = }b\cdot(x-7a)\text{ + 3ab}

Whenever we have algebraic expressions we always refer to the rule of ( PEMDAS ).

Step 1: Solve the Parenthesis

We will solve for all the parenthesis in the equation given and write down the result:

3bx\text{ - 6ab = bx - 7ab + 3ab }

Step 2: Highlight and combine the like terms

All like terms are classified on the basis of their constants ( a and b ) and variable ( x ) attached. We will highlight all the like terms and take simplify them on either side of the " = " sign:

\begin{gathered} 3bx\text{ }\text{\textcolor{#FF7968}{- 6ab}}\text{ = bx }\text{\textcolor{#FF7968}{-7ab}}\text{ }\text{\textcolor{#FF7968}{+ 3ab}} \\ 3bx\text{ - bx = 2ab} \end{gathered}

We combined three like terms ( -6ab , -7ab , and 3ab ).

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We are left with a simple expression that relates the constant ( a ) and variable ( x ). We can go ahead and solve for the above:

\begin{gathered} x\text{ = }\frac{2a}{2} \\ \textcolor{#FF7968}{x}\text{\textcolor{#FF7968}{ = a}} \end{gathered}

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Answer:

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12+5t−4+15t+1

20t + 9

(Simplified version)

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