Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Answer:
21 hours
Explanation:
well 30 x 20 = 600 than 21 = 630
Answer:
Explanation:
The time lag between the arrival of transverse waves and the arrival of the longitudinal waves is defined as:
Here d is the distance at which the earthquake take place and 
is the velocity of the transverse waves and longitudinal waves respectively. Solving for d:
The object is not moving.
My explanation is that say if you sit a ball on the table and it is a smooth surface with no bumps or anything. The ball will sit still since it can’t roll unless you hit it.
Hope this helps!
<h2>Hello!</h2>
The answer is: There are 3.42 moles of MgCl2 in 326g of the compound.
<h2>Why?</h2>
Assuming that the compound is MgCl2, we can find how many moles of the compound are in 326 g of the same compound, calculating the molar mass of the compound, so:
Then,
Therefore, to calculate how many moles are in 326 of the compound, we can use the following equation
Hence,
There are 3.42 moles of MgCl2 in 326g of the compound.
Have a nice day!
