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cestrela7 [59]
3 years ago
6

What are the parts of an atom

Physics
2 answers:
Ivenika [448]3 years ago
7 0
Number three

They contain protons (positive), neutrons (negative), electrons (neutral) and all are in a nucleus which is part of an atom
nekit [7.7K]3 years ago
3 0
It's number 2 I think. electrons, protons and neutrons. protons and neutrons in nucleus electrons outside. exception being "normal" hydrogen. one proton and one electron with no neutrons.
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What is the magnitude of the gravitational force of attraction between two 0.425-kilogram soccer balls when the distance between
Lapatulllka [165]

<u>Answer</u>

4.8212×10⁻¹¹ N


<u>Explanation</u>

The gravitational force F, between 2 masses m₁ and m₂ is given by:

F = (Gm₁m₂)/d²

Where G =  6.673 x 10⁻¹¹ N m²/kg² and d is the distance between the 2 masses.

F = (Gm₁m₂)/d²

   =  (6.673 x 10⁻¹¹ × 0.425 × 0.425)/0.500²

   = 1.2053×10⁻¹¹/0.25

   = 4.8212×10⁻¹¹ N

7 0
3 years ago
a car moving on a road passes by kilometer 218 at 10:15 am and milestone 236 at 10:30 am. determine an average scalar speed in k
Leno4ka [110]

Answer:

v?

Explanation:

v = ∆s / ∆t

v =?

∆s = 236 - 218 = 18km

=t = 10: 30 - 10:15 = 15 minutes to hour 15/60 = 0.25h

v = 18 / 0.25

v = 72km / h

speed of 72km / h

5 0
3 years ago
How does air resistance affect forward motion
lord [1]

It creates friction on the forward moving object, causing it to loose momentum, until finally, it stops.

Hope this helps!

8 0
3 years ago
Read 2 more answers
How does the thickness of wood affect its stability
Law Incorporation [45]

Answer:

Making the lumber thick will make it stiff, which seems good. On the other hand, with thicker lumber, differences in expansion on the two faces have more leverage to make the lumber move.

7 0
3 years ago
A car traveling at 20 m/s when the driver sees a child standing in the road. He takes 0.80 s to react, then steps on the brakes
mr Goodwill [35]

When driver see the child standing on road his speed is 20 m/s

So here at that instant his reaction time is 0.80 s

He will cover a total distance given by product of speed and time

d_1 = v* t

d_1 = 20 * 0.8

d_1 = 16 m

now after this he will apply brakes with acceleration a = 7 m/s^2

so the distance covered before it stop is given by

v_f^2 - v_i^2 = 2 a d

0 - 20^2 = 2*(-7)*d_2

d_2 = 28.6 m

so the total distance covered by it

d = d_1 + d_2

d = 16 + 28.6 = 44.6 m

<em>so it will cover a total distance of 44.6 m</em>

3 0
3 years ago
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