Figure 3 shows a stationary metal block hanging from the middle of a stretched wire which is suspended from a horizontal beam. T
he tension in each half of the wire is 15 N. (a) Calculate for the wire at A, (i) the resultant horizontal component of the tension forces, (ii) the resultant vertical component of the tension forces. Can someone explain why the first one is 0?
1 answer:
Explanation:
(i) The horizontal component of the tension in the right wire points right, and the horizontal component of the tension in the left wire points left. Since these components are equal and opposite, the resultant horizontal force is 0.
∑Fₓ = 15 N cos 20° − 15 N cos 20°
∑Fₓ = 0 N
(ii) ∑Fᵧ = 15 N sin 20° + 15 N sin 20°
∑Fᵧ = 10.26 N
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Answer:
The angular speed of the object is 0.0281 rad/s
The linear speed of the object is 0.169 ft/s
Explanation:
Given;
radius of the circle, r = 6 ft
time of motion of the object around the circle, t = 80 s
central angle formed by the object during the motion, θ = 9/4 rad = 2.25 rad
The angular speed of the object is calculated as;
The linear speed of the object is calculated as;
v = ωr
v = 0.0281 rad/s x 6ft
v = 0.169 ft/s