Figure 3 shows a stationary metal block hanging from the middle of a stretched wire which is suspended from a horizontal beam. T
he tension in each half of the wire is 15 N. (a) Calculate for the wire at A, (i) the resultant horizontal component of the tension forces, (ii) the resultant vertical component of the tension forces. Can someone explain why the first one is 0?
1 answer:
Explanation:
(i) The horizontal component of the tension in the right wire points right, and the horizontal component of the tension in the left wire points left. Since these components are equal and opposite, the resultant horizontal force is 0.
∑Fₓ = 15 N cos 20° − 15 N cos 20°
∑Fₓ = 0 N
(ii) ∑Fᵧ = 15 N sin 20° + 15 N sin 20°
∑Fᵧ = 10.26 N
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Answer:
a. 2143 turns/m
b. 111.5 m
Explanation:
a. The minimum number of turns per unit length (N/L) can be found using the following equation:
Hence, the minimum number of turns per unit length is 2143 turns/m.
b. The total length of wire is the following:
Since each turn has length 2πr of wire, the total length is:
Therefore, the total length of wire required is 111.5 m.
I hope it helps you!