Answer: 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.
Explanation:
The balanced chemical equation is:
To calculate the moles, we use the equation:
moles of manganese =
According to stoichiometry :
3 moles of is produced by = 3 moles of
Thus 20.4 moles of is produced by = of
Mass of (1kg=1000g)
Thus 1.77 kg of manganese (IV) oxide reacts to produce 1.12kg of manganese metal.
<u>Answer:</u> The normality of unknown acid solution is 0.232 N
<u>Explanation:</u>
To calculate the normality of the unknown acid solution, we use the equation:
where,
are the normality and volume of the unknown acid solution
are the normality and volume of NaOH solution
We are given:
Putting values in above equation, we get:
Hence, the normality of unknown acid solution is 0.232 N
The correct answer for the question that is being presented above is this one: "C) The reaction is spontaneous at high temperatures."
Since dH is positive and dS ~ 0 then -TdS ~ 0, meaning dG will always be greater than 0 so t<span>he reaction is spontaneous at high temperatures.</span>
<span>The student should
follow following steps to make 1 L of </span>2.0 M CaCl₂.<span>
<span>
1. First he should
calculate the number of moles of 2.0 M CaCl</span></span>₂ in 1 L solution.<span>
</span>Molarity of the solution = 2.0 M<span>
Volume of solution which should be prepared = 1 L
Molarity =
number of moles / volume of the solution
Hence, number of moles in 1 L = 2 mol
2. Find
out the mass of dry CaCl</span>₂ in 2 moles.<span>
moles =
mass / molar mass
Moles of CaCl₂ =
2 mol</span><span>
Molar mass of CaCl₂ = </span><span>110.98 g/mol
Hence, mass of CaCl</span>₂ = 2 mol x <span>110.98 g/mol
= 221.96
g
3. Weigh the mass
accurately
4. Then take a cleaned and dry1 L volumetric flask and place a funnel top of it. Then carefully add the salt into the volumetric flask and
finally wash the funnel and watch glass
with de-ionized water. That water also should be added into the volumetric
flask.
5. Then add some
de-ionized water into
the volumetric flask and swirl well until all salt are
dissolved.
<span>6. Then top up to
mark of the volumetric flask carefully.
</span></span>
7. As the final step prepared solution should be labelled.
Answer:
3 NiSO₄(aq) + 2 (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + 3 (NH₄)₂SO₄
Explanation:
<em>The question is missing but I think it must be about writing and balancing the equation.</em>
Let's consider the unbalanced reaction that occurs when aqueous solutions of nickel(II) sulfate and ammonium phosphate are combined to form solid nickel(II) phosphate and a solution of ammonium sulfate. This is a double displacement reaction.
NiSO₄(aq) + (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + (NH₄)₂SO₄
We will start balancing Ni atoms by multiplying NiSO₄ by 3.
3 NiSO₄(aq) + (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + (NH₄)₂SO₄
Now, we have to balance S atoms by multiplying (NH₄)₂SO₄ by 3.
3 NiSO₄(aq) + (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + 3 (NH₄)₂SO₄
Then, we need to balance N atoms by multiplying (NH₄)₃PO₄ by 2. This will be the balanced equation.
3 NiSO₄(aq) + 2 (NH₄)₃PO₄(aq) ⇒ Ni₃(PO₄)₂ + 3 (NH₄)₂SO₄