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3 years ago

9

Math question, need help

2 answers:

AleksandrR [38]3 years ago

5 0

Answer:

$\boxed{\red{2x - 1 = 5x - 14}}$

First answer is correct.

Step-by-step explanation:

we know that,

${x}^{a} = {x}^{b}$

$a = b$

So, according to that,

${5}^{(2x - 1)} = {5}^{(5x - 14)}$

Therefore,

$2x - 1 = 5x - 14$

Iteru [2.4K]3 years ago

3 0

In general, if we have $x^a=x^b,$ then $a=b.$ Thus, the first answer choice is correct.

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The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?

Paul [167]

Answer:

The standard form of the given circle is

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Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is $M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (6,2) and (-2,5) respectively.

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$M=(\frac{4}{2},\frac{7}{2})$

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Therefore the center (h,k) is $(2,\frac{7}{2})$

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The diameter is the distance between the given points (6,2) and (-2,5)

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$(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2$

$(x-2)^2+(y-\frac{7}{2})^2=73$

Therefore the standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

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