All categories

3 years ago

In water, hydrogen bonding occurs between the hydrogen atom in one molecule and __________.

Chemistry

1 answer:

trapecia [35]3 years ago

5 0

Answer: B) an oxygen atom in a different molecule.

Explanation:

Hydrogen bonding (H-bonding) is an inter molecular force having partial ionic-covalent character.

H-bonding takes place between a hydrogen atom attached with an electronegative atom such as O, N and F and an electronegative atom such as O,N and F. They are strong forces.

Example: $H_2O$ has hydrogen bonding between hydrogen of one molecule with oxygen atom bonded to hydrogen of different molecule.

Thus the correct option is hydrogen bonding occurs between the hydrogen atom in one molecule and an oxygen atom in a different molecule.

You might be interested in

What is a star that collapsed under gravity called?

Ratling [72]

Neutron Star hope this helps

5 0

3 years ago

Read 2 more answers

Which of the following mass units is the largest? a) 1 cg b) 1 dg c) 1 mg d) 1 ng

N76 [4]

Answer: option b) 1 dg

Explanation:

1) These are the different equivalences of those quantities:

a) 1 g = 100 cg ⇒ 1 cg = 0.01 g

b) 1 g = 10 dg ⇒ 1 dg = 0.1 g

c) 1 g = 1000 mg ⇒ 1 mg = 0.001 g

d) 1g = 10⁹ g ⇒ 1 ng = 10 ⁻⁹g

2) Now that you have all the masures in grams you can compare:

0.1g > 0.01g > 0.001g > 10 ⁻⁹g

3) So, the largest value is 0.1g which is 1 dg.

4 0

4 years ago

Read 2 more answers

What type of wave is it ?

il63 [147K]

Answer:

transverse wave

Explanation:

5 0

3 years ago

If 36.2g of Acetic Acid (HC2H302) was dissolved in 300. mL of water, what is the

uysha [10]

Answer:

2.01 M

Explanation:

Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)

The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.

$36.2g \times \frac{1mol}{60.05g} = 0.603mol$

Step 2: Convert the volume of solution to liters

We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)

$300mL \times \frac{1L}{1000mL} = 0.300L$

Step 3: Calculate the molarity of the solution

The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution

$M = \frac{0.603mol}{0.300L} = 2.01 M$

7 0

3 years ago

At 500°C the equilibrium constant, Kp, is 4.00 × 10–4 for the equilibrium: 2HCN(g) H2(g) + C2N2(g) What is Kp for the following

Andrews [41]

Answer: The value of $K_p$ for the equation is $2.5\times 10^3$

Explanation:

The given chemical reaction is:

$2HCN(g)\rightleftharpoons H_2(g)+C_2N_2(g);K_1$

The chemical equation for which the equilibrium constant is to be calculated follows:

$H_2(g)+C_2N_2(g)\rightleftharpoons 2HCN(g);K_p$

As, the equation is the result of the reverse of given reaction. So, the equilibrium constant for the equation will be the inverse of equilibrium constant for the given reaction.

The value of equilibrium constant for the equation is:

$K_p=\frac{1}{K_1}$

We are given:

$K_1=4.00\times 10^{-4}$

Putting values in above equation, we get:

$K_p=\frac{1}{4.00\times 10^{-4}}=2.5\times 10^3$

Hence, the value of $K_p$ for the equation is $2.5\times 10^3$

3 0

4 years ago