C is correct.
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Answer:
D. C=O
Explanation:
Esters are formed by the condensation of alcohols and acids with minus water. During the reaction, at least one -OH group is replaced by an O- alkyl group. The resulting compound is an ester and has a characteristic fruity smell. Its functional group is C=O
London dispersion is present, as we can see C3H5(OH)3 is very branched, when a molecule is branched it has a low boiling point due to how compact the surface area is compare to C3H7OH which has a large surface area (in this molecule there is only on branch)
There would be no net movement of glucose
The given statement is wrong. Glucose solutions are not electrolytes and therefore do not conduct electricity.
Is sodium chloride a good conductor of electricity? Simply by dissolving or dissolving it in water, it cannot conduct electricity as a solid.
Saline contains Na+ and Cl- ions. If ions are present in the solution, these ions can move through the solution and carry an electric current. Pure water and sugar solutions do not contain significant ions. Sugar molecules do not break down into ions when dissolved.
When glucose is added to water, it dissolves readily but does not dissociate into ions. Therefore, a glucose solution is not an electrolyte and is not a conductor of electricity.
Substances that dissolve in water to form a conductive solution are called electrolytes. Substances that dissolve in non-conductive solutions are called non-electrolytes. All soluble ionic compounds are electrolytes.
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Rb > I > Na
Rubidium have lowest ionisation energy due to larger size and less electronegativity!
