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2 years ago

What happens if the solvent solute attraction is greater than the salute solute attraction when to substances are mixed

Chemistry

1 answer:

dolphi86 [110]2 years ago

5 0

Answer:

What happens if the solvent-solute attraction is greater than the solute-solute attraction when two substances are mixed? The solute particles are pulled apart and dispersed throughout the particles of the solvent, which holds the particles of the solute in solution.

Explanation:

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2. The Food and Drug Administration (FDA) mandates that all vinegar sold in the United States must have a minimum concentration

Scilla [17]

Answer:

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

Explanation:

4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.

Given that density of the vinegar is same is that of water = 1 g/mL

Mass of the vinegar solution = 100 g

Volume of the vinegar solution = V

$Density=\frac{Mass}{Volume}$

$1 g/mL=\frac{100 g}{V}$

V = 100 mL = 0.1 L

Moles of acetic acid = $\frac{4 g}{60.052 g/mol}=0.0666 mol$

$Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}$

$M=\frac{0.0666 mol}{0.1 L}=0.6660 mol/L$

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

4 0

3 years ago

The boiling point of water is 100.0°C at 1 atmosphere. How many grams of sodium acetate (82.04 g/mol), must be dissolved in 283.

Alecsey [184]

Answer:

I have to weight 10,04 g of acetate sodium

Explanation:

This is the colligative propertie about elevation of boiling point

ΔT = Kb . m . i

ΔT is the difference between T° at boiling point of the solution - T° at boiling point of the solvent pure - we have this data 0,450°C

Kb means ebulloscopic constant (0,52 °C.kg/m .- a known value for water)

m means molality (moles of solute in 1kg of solvent)

i means theVan 't Hoff factor (degree of dissociation for a compound)

For the sodium acetate is 2

NaCH3COO ---> Na+ + CH3COO-

0,450°C = 0,52°C.kg/m . m . 2

0,450°C / (0,52°C.kg/m . 2) = m

0,432 m/kg = m

This number means I have 0,432 moles of acetate sodium, my solute in 1kg of water, my solvent. But I don't have 1000 g (1kg) I only have 283 g so let's make the rule of three:

1000 g _____ 0,432 moles

283 g ______ (283g .0,432m) / 1000g = 0,122 moles

Now that I have the moles of acetate sodium, I have to find the mass.

Moles . molar mass = mass

0,122 moles . 82.04 g/mol = 10,04 g

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3 years ago

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Students can use _________ to distinguish pure substances, such as elements and compounds with a constant composition, from othe

ollegr [7]

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3 years ago

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How many grams of fluorine are contained in 8 molecules of boron trifluoride?

Lelu [443]

<h3>Answer:</h3>

7.57 × 10⁻²² g of F

<h3>Solution:</h3>

Data Given:

Number of Molecules = 8

M.Mass of BF₃ = 67.82 g.mol⁻¹

Mass of Fluorine atoms = ?

Step 1: Calculate Moles of BF₃

Moles = Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Putting value,

Moles = 8 Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Moles = 1.33 × 10⁻²³ mol

Step 2: Calculate Mass of BF₃:

Moles = Mass ÷ M.Mass

Solving for Mass,

Mass = Moles × M.Mass

Putting values,

Mass = 1.33 × 10⁻²³ mol × 67.82 g.mol⁻¹

Mass = 9.0 × 10⁻²² g

Step 3: Calculate Mass of Fluorine Atoms:

As,

67.82 g BF₃ contains = 57 g of F

So,

9.0 × 10⁻²² g will contain = X g of F

Solving for X,

X = (9.0 × 10⁻²² g × 57 g) ÷ 67.82 g

X = 7.57 × 10⁻²² g of F

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3 years ago

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2 years ago