All categories

3 years ago

Which reflects more energy, the atmosphere and clouds or the surface?

Chemistry

2 answers:

LenKa [72]3 years ago

8 0

Answer:

the surface

Explanation:

n/a

Anastaziya [24]3 years ago

5 0

Answer: clouds

Explanation:

The clouds reflect 23%

You might be interested in

Naming compounding N2O

solniwko [45]

Answer:

Nitrogenous oxide/ nitrogen oxide

Explanation:

N2O is nitrogen oxide

6 0

2 years ago

Hhhhhhhhhhheeeeeeelppppppp will give brainliest

wlad13 [49]

Answer:

Kinetic energy.

Explanation:

7 0

2 years ago

During the water cycle, the sun's energy evaporates water from the surface of Earth. This water is the source of A) respiration.

LuckyWell [14K]

This water source is called precipitation

8 0

2 years ago

The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con

bonufazy [111]

Answer: The concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

Explanation:

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

We are given:

$t_{1/2}=3.82days$

Putting values in above equation, we get:

$k=\frac{0.693}{3.82}=0.181days^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.181days^{-1}$

t = time taken for decay process = 3.00 days

$[A_o]$ = initial amount of the reactant = $1.45\times 10^{-6}mol/L$

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}$

$[A]=3.83\times 10^{-30}mol/L$

Hence, the concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

7 0

3 years ago

Fofrffycfcfyguffucggr

ira [324]

Answer:

In his alien language, he said ¨ Hellooooo human¨

Explanation:

4 0

2 years ago