Answer:
70.0 %
Explanation:
Step 1: Given data
- Mass of nitrogen (mN): 74.66 g
- Mass of the compound (mNxOy): 250 g
Step 2: Calculate the mass of oxygen (mO) in the compound
The mass of the compound is equal to the sum of the masses of the elements that form it.
mNxOy = mN + mO
mO = mNxOy - mN
mO = 250 g - 74.66 g = 175 g
Step 3: Determine the percent composition of oxygen in the sample
We will use the following expression.
%O = mO / mNxOy × 100%
%O = 175 g / 250 g × 100% = 70.0 %
Answer:
Cm = Cn/n = 0.1/2 = 0.05 (M)
n = 0.05*2= 0.1 mol
m H2SO4= 0.1*98= 9.8 g
m dd H2SO4= 9.8/ 0.98 =10 g
V= 10/ 1.84 = 5.435 ml
Explanation:
Answer:
25.6mL NaOH
Explanation:
We are given the Molarity of the solution (
) and the volume of the solution (.02L).
By multiplying the two together, we can find the moles of solution that are reacted with HCl.
This gives us .0082 moles of HCl.
We then find the moles of NaOH that are needed to react with the HCl using the equation.
As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.
Dividing this value by the Molarity of the solution
Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.
Rearrange the equation n=M÷Mr. Where n = the number of moles. M= the mass in grams. And Mr = the molecular mass of the substance.
Since you are working out mass use the equation M= n x Mr. So you have
6.21 × 111 (molecular mass of CaCl2).
This will give you the answer 689.31 grams which would be your final answer.
Answer:
74 % major, 26 % minor product
Explanation:
The total area under the peaks is
85 units + 30 units = 115 units
