Answer:
d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels.
Explanation:
a ) a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration.
It has negative acceleration in the negative x-direction.
b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration.
It has a positive acceleration in the negative x-direction'
c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels.
It has a positive acceleration in opposite direction.
e ) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.
It has a positive acceleration only in opposite direction .
The unit of measurement for mass & weight is kilograms (kg)
Answer:
The time interval is 22.76 hr.
Explanation:
Given that,
Time = 30 hrs
Speed = 0.74c
We need to calculate the time interval measured in earth frame
Using formula of time dilation
Where, = time interval measured in earth frame
=proper time interval
Put the value into the formula
We need to calculate the proper time interval when the velocity is 0.86c
Using formula of time dilation
Hence, The time interval is 22.76 hr.
a) create an expression
for the ball's initial horizontal velocity, V0x, in terms of the variables
given in the problem statement.
v0x = vf * cos(Θf)
<span>
b) calculate the ball's initial vertical velocity, V0y, in
m/s</span>
v0x = 32.4m/s * cos(-25.5º)
= 29.2 m/s <span>
tanΘ = v1y / v0x → tan(-25.5) = v1y / 29.2m/s → v1y = -13.93
m/s
the vertical velocity when the ball was caught.
(v0y)² = (v1y)² + 2as = (-13.93m/s)² + 2 * 9.8m/s² * 5.5m = 301.78
m²/s²
v0y = 17.37 m/s
c) calculate the magnitude of the ball's initial velocity,
v0, in m/s</span>
v0 = sqrt (v0y^2 +
v0x^2)
v0 = sqrt (17.37^2 + 29.2^2)
m/s
v0 = 33.98 m/s
<span>
d) find the angle, theta0, in degrees above the horizontal at
which which the ball left the bat.</span>
tan Θ = v0y/v0x
<span>Θ = arctan(17.37/29.2) =
30.75º above horizontal</span>
Answer:
conduction electrons
Explanation:
Metallic bonding is a type of chemical bonding that rises from the electrostatic attractive force between conduction electrons and positively charged metal ions. It may be described as the sharing of free electrons among a structure of positively charged ions.