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Valentin [98]
3 years ago
12

A 15 kg mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the total work that must be done

on the mass to increase it's speed to 11.5 meters per second?
Physics
1 answer:
sashaice [31]3 years ago
8 0
Kinetic energy = (1/2) (mass) x (speed)²

At 7.5 m/s, the object's KE is (1/2) (7.5) (7.5)² = 210.9375 joules

At 11.5 m/s, the object's KE is (1/2) (7.5) (11.5)² = 495.9375 joules

The additional energy needed to speed the object up from 7.5 m/s
to 11.5 m/s is (495.9375 - 210.9375) = <em>285 joules</em>.

That energy has to come from somewhere. Without friction, that's exactly
the amount of work that must be done to the object in order to raise its
speed by that much.
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In solution the particles of solute dissolve in to the solvent. We cannot identify them as separate. We cannot separate them by filtration. Salt and water solution is an example of it. Evaporation is the technique that is required to separate them.

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