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3 years ago

Andrew skis down a hill.

Physics

1 answer:

IceJOKER [234]3 years ago

5 0

Explanation:

gravitational potential energy at the top of the hill, which transforms into kinetic energy as he moves bottom of the hill

that's mean potential energy transfoms into kinetic energy

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3 years ago

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If the 0.09-mm-diameter tungsten filament in a light bulb is to have a resistance of 0.11 Ω at 20∘C, how long should it be?

skad [1K]

Answer:

Length L=0.0125 m

Explanation:

Given data

Resistance R=0.11Ω

Temperature T=20°C

Resistivity of tungsten at 20°C p=5.6×10⁻⁸Ω.m²

Radius of filament r=0.09/2 =0.045 mm =0.045×10⁻³m

To find

Length of filament L

Solution

The Cross section of area of filament is given as:

$A=\pi r^{2}\\ A=\pi (0.045*10^{-3})^{2}\\A=6.3585*10^{-9}m^{2}$

The Resistance of a material is given as:

$R=p\frac{L}{A} \\L=\frac{AR}{p}\\ L=\frac{(6.3585*10^{-9})(0.11)}{5.6*10^{-8}}\\L=0.125m$

6 0

3 years ago

A system has 4 independent and identical motors, in order for the system to work, at least one of the motors must operate. Each

grin007 [14]

Answer:

The system's Mean Time to Failure is 1,041. $\bar 6$ hours

Explanation:

The number of independent identical motors = 4

The failure rate of each motor, λ = 0.002 failures per hour

Given that in order for the system to work, at least one of the motors must operate, therefore, the system are in parallel

The Mean Time to Failure for a parallel system of four identical components is given as follows;

$MTTF = \dfrac{1 }{\lambda} \times \left (1 + \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{4} \right)$

Which gives;

$MTTF = \dfrac{1 }{0.002} \times \left (1 + \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{4} \right) = 1,041.\bar 6$

The system's Mean Time to Failure = 1,041. $\bar 6$ hours.

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3 years ago