Answer:
light scattering by particles in a colloid or in a very fine suspension
Answer:
The electric force will be 0 N
Explanation:
From the question we are told that
The magnitude of the charge is 
Generally from Coulombs law the electric force between two charges is mathematically represented as

Here r is the distance of separation between that two charges.
Now from the question we are told that the charge is far away from any other charge hence we can say that the distance between the charge and any other charge is 
So

=> 
Hence the electric force will be 0 N
Sorry for the messy handwriting but this is what I got
Answer: On the basis of speed they are all equivalent.
Yellow light = Fm radio wave = Green light = X-ray = AM radio wave = Infrared wave
Explanation:
Yellow light, Fm radio wave, Green light ,X-ray, AM radio wave and Infrared wave are all electromagnetic waves, and all electromagnetic waves move at the same vacuum speed which is the speed of light and is approximately 3.0x10^8 m/s.
They only differ in wavelength and frequency
c = λf
c (speed of light) = λ (wavelength) x f (frequency)
Therefore; on the basis of speed they are all equivalent.
Yellow light = Fm radio wave = Green light = X-ray = AM radio wave = Infrared wave
To answer this question, we should know the formula for the terminal velocity. The formula is written below:
v = √(2mg/ρAC)
where
m is the mass
g is 9.81 m/s²
ρ is density
A is area
C is the drag coefficient
Let's determine the mass, m, to be density*volume.
Volume = s³ = (1 cm*1 m/100 cm)³ = 10⁻⁶ m³
m = (1.6×10³ kg/m³)(10⁻⁶ m³) = 1.6×10⁻³ kg
A = (1 cm * 1 m/100 cm)² = 10⁻⁴ m²
v = √(2*1.6×10⁻³ kg*9.81 m/s²/1.6×10³ kg/m³*10⁻⁴ m²*0.8)
<em>v = 0.495 m/s</em>