How do I calculate the resistance in a circuit in which a 9-volt battery produces 3 amperes

A biologist looking through a microscope sees a bacterium at r⃗ 1=2.2i^+3.7j^−1.2k^μm(1μm=10−6m). After 6.2 s , it's at r⃗ 2=4.6

stiv31 [10]

The Average velocity for the bacterium is 0.75 unit/sec.

<u>Explanation:</u>

The given values are in the vector form

Where,

dS = distance covered

dT = time interval

Now, to calculate distance covered, we have

$|d S|=\sqrt{d S^{2}}$

&

$d S=r_{2}-r_{1}$

d S=(4.6 i+1.9 k)-(2.2 i+3.7 j - 1.2 k)

d S=(4.6-2.2) i+(0-3.7) j+(1.9+1.2) k

d S=2.4 i-3.7 j+3.1 k

Now, putting these values in the standard formula to evaluate the average velocity, we get;

$v_{a v g}=\frac{|\mathrm{d} S|}{d T}$

$v(a v g)=\frac{|\sqrt{\left\{\left(2.4^{2}\right)+\left(3.7^{2}\right)+\left(3.1^{2}\right)\right\}}|}{7.2}$

As dT=7.2 sec

Now,

Solving the equation, we get;

$v(a v g)=\frac{5.390732789}{7.2}$

$\begin{aligned}&v(a v g)=\frac{5.39}{7.2}\\&v(a v g)=0.748611111\\&v(a v g)=0.75 \text { units / sec }\end{aligned}$

Hence, the average velocity for the bacterium is 0.75 unit/sec.

3 0

3 years ago

If you decrease the length of a wire, what effect will it have on resistance

attashe74 [19]

As the length increases, resistance increases, as a result current decreases.

7 0

4 years ago

The prevailing winds that form in Hadley cells are _____.

dmitriy555 [2]

Answer = C

It blows towards the poles from the sub-tropical high pressure areas

8 0

3 years ago

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Water is poured into a bowl at a constant rate of 17.0 cm^3/s. The bowl has a circular cross section, but does not have a unifor

7nadin3 [17]

Answer:

10.29 cm/s

Explanation:

Discharge in to the bowl = 17.0 cm³/s

Diameter of the bowl, d₁ = 1.45 cm

Now,

Rate at which water level rise at its diameter = $\frac{\textup{Discharge}}{\textup{Area of cross-section}}$

also,

Area of cross-section = $\frac{\pi}{\textup{4}}\times1.45^2$

or

Area of cross-section = 1.651 cm²

Therefore,

Rate at which water level rise at its diameter = $\frac{\textup{17}}{\textup{1.651}}$

or

Rate at which water level rise at its diameter = 10.29 cm/s

8 0

4 years ago

body starting from rest and moving with an uniform acceleration of 3 m/s²..What is its velocity after 15s?

Luba_88 [7]

<h2>Answer :</h2>

□ The Final velocity of body = 45 m/s $\sf{ }$

<h2>Given :</h2>

Initial velocity of body = 0 m/s

Acceleration of body = 3 m/s²

Time taken by body = 15 sec

<h2>To Calculate :</h2>

Final velocity of body = ?

<h2>How To Calculate ?</h2>

Here in this question we are provided that a body is in rest so it's initial velocity will be 0 m/s (because from rest), Acceleration of body is 3 m/s², and Time taken is also given which is 15 sec.

To calculate the Final velocity of body we'll use the first equation of motion which says v = u + at

Where,

v is the Final velocity in m/s.

u is the Initial velocity in m/s.

a is the Acceleration in m/s².

t is the Time taken in second.

<h2>Calculation :</h2>

From first equation of motion

⇒ v = u + at

⇒ v = 0 + 3 × 15

⇒ v = 0 + 45

⇒ v = 45

Hence, the Final velocity of body is 45 m/s.

7 0

3 years ago

Read 2 more answers