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user100 [1]
3 years ago
5

A company, which makes forging die wants to improve their steel parts and they contacted you because they heard you know a techn

ology using martensitic transformation to make the surface of their steel product hard. The company selected AISI 1008 steel for their product, but after heat treatment they have no idea how to verify whether the heat treatment did a sufficient job or not.
a. What test will tell whether the heat treatment was good enough?
b. If you have hardness test among the potential testing methods in the list what kind of hardness tests are available and what specific hardness test are you going to suggest to the company? And why?
c. After suggesting the methodology to the company, the company engineer came back with a very low hardness value. What went wrong?
d. What is the solution you want to provide to the company and why?
Engineering
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

a

Hardness Test

b

The available hardness test are

  • Rockwell hardness test
  • Vicker's hardness test
  • knoop test
  • scratch test
  • Brinell hardness test e.t.c

I would suggest Rockwell test because

  • It has good accuracy
  • In this test loads can be applied in 2 stages hence better results are obtained
  • it saves time because it testing are faster

c

   Well the following would be the reasons for low hardness value

  • It could be because the steel used has a low percentage of carbon
  • it could also result from the quenching medium used (e.g water , brine solution e.t.c)

d

In order to solve this problem here are the following ways

  • When selecting steel the ones with a carbon percentage 0.3% to 0.8% should be selected
  • When quenching the quenching medium should be brine solution  

Explanation:

The reason why the answer to question is hardness test is because the heat treatment was carried out to obtain hardness so if it is great then the heat treatment is good

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Answer:

The p-n junction is a region formed when a p -type semiconductor material is joined to an n-type semiconductor material

Explanation:

The p type semiconductor has holes as its majority charge carriers making it positively charged while the n –types has an overall negative charge. At the junction the holes move towards the electron until such a time when there is a balance in charges from both materials, which leads to the formation of the depletion zone as shown in the attachment below

                           

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The present worth of income from an investment that follows an arithmetic gradient is projected to be $475,000. The income in ye
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Explanation:

I found this on another site:

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4 0
3 years ago
Write a C++ program to display yearly calendar. You need to use the array defined below in your program. // the first number is
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Answer:

//Annual calendar

#include <iostream>

#include <string>

#include <iomanip>

void month(int numDays, int day)

{

int i;

string weekDays[] = {"Su", "Mo", "Tu", "We", "Th", "Fr", "Sa"};

// Header print

      cout << "\n----------------------\n";

      for(i=0; i<7; i++)

{

cout << left << setw(1) << weekDays[i];

cout << left << setw(1) << "|";

}

cout << left << setw(1) << "|";

      cout << "\n----------------------\n";

      int firstDay = day-1;

      //Space print

      for(int i=1; i< firstDay; i++)

          cout << left << setw(1) << "|" << setw(2) << " ";

      int cellCnt = 0;

      // Iteration of days

      for(int i=1; i<=numDays; i++)

      {

          //Output days

          cout << left << setw(1) << "|" << setw(2) << i;

          cellCnt += 1;

          // New line

          if ((i + firstDay-1) % 7 == 0)

          {

              cout << left << setw(1) << "|";

              cout << "\n----------------------\n";

              cellCnt = 0;

          }

      }

      // Empty cell print

      if (cellCnt != 0)

      {

          // For printing spaces

          for(int i=1; i<7-cellCnt+2; i++)

              cout << left << setw(1) << "|" << setw(2) << " ";

          cout << "\n----------------------\n";

      }

}

int main()

{

int i, day=1;

int yearly[12][2] = {{1,31},{2,28},{3,31},{4,30},{5,31},{6,30},{7,31},{8,31},{9,30},{10,31},{11,30},{12,31}};

string months[] = {"January",

"February",

"March",

"April",

"May",

"June",

"July",

"August",

"September",

"October",

"November",

"December"};

for(i=0; i<12; i++)

{

//Monthly printing

cout << "\n Month: " << months[i] << "\n";

month(yearly[i][1], day);

if(day==7)

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day = 1;

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day = day + 1;

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cout << "\n";

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return 0;

}

//end

3 0
4 years ago
A particle moving on a straight line has acceleration a = 5-3t, and its velocity is 7 at time t = 2. If s(t) is the distance fro
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Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7

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We have

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= \int\limits^a_b {(5-3t)} \, dt

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= 10-6+c

= 4+c

s(t) = \frac{5t^2}{2} -\frac{t^3}{2} +3t + c

S2 - S1

=(5*\frac{4}{2} -\frac{8}{2} +3*2*c)-(\frac{5}{2} *1^2-\frac{1^2}{2} +3*1*c)

= 6 + 6+c - 2+3+c

12+c-5+c = 0

7 = c

Read more on acceleration here: brainly.com/question/605631

5 0
2 years ago
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