Someone please explain molecular orbital in Xenon difluoride ( XeF2).

When you finish using a microscope, you have to take out all your samples you were using and make sure it is completely clean so that no further contamination affects future sample analysis.

Also when you begin to use it, make sure it is clean so that when you analyze your sample(s) are free from other unexpected agents.

5 0

4 years ago

In the cathode ray tube experiment, J. J. Thomson passed an electric current through different gases inside a cathode ray tube i

Ber [7]

It showed that atoms can be divided into smaller parts.

It showed that all atoms contain electrons.

Explanation:

The experiment carried out by J.J Thomson on the gas discharge tube by passing electric current through a tube filled with many different gases provided a good insight into the structure of an atom.

This experiment led to the development of the plum pudding model of the atom.

Cathode rays and it properties were discovered in this set up.
It furnished the scientific community with evidences that atoms can be divided into smaller parts.
Since atoms now contain some subatomic particles, they can be broken down in like manner into further bits.
The cathode rays which were later termed electrons became a fundamental particles known for every atom.

learn more:

Rutherford's model of the atom brainly.com/question/1859083

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6 0

3 years ago

Read 2 more answers

Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,

vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

$N=n\times N_A$

Where : N = Number of atoms

n = moles

$N_A=6.022\times 10^{23}$ = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol × 44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol × 8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol

Mass percentage of gold :

$\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=33.35 \%$

Mass percentage of silver:

$\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=62.80\%$

Mass percentage of copper :

$\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=3.85\%$

7 0

3 years ago

Someone please explain molecular orbital in Xenon difluoride ( XeF2).​

Someone please explain molecular orbital in Xenon difluoride ( XeF2).