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Grace [21]
3 years ago
7

Several properties of the element magnesium are shown. Which one is a chemical property?

Chemistry
1 answer:
mixer [17]3 years ago
3 0

The exterior of magnesium metal is shielded with a thin layer of oxide that somewhat protects the metal from attack by air. Magnesium metal burns in air with a distinctive blinding bright white spark when ignited to give a mixture of white magnesium oxide, MgO, and magnesium nitride, Mg3N2. Magnesium is highly reactive to halogens such as chlorine, Cl2 or bromine, Br2, and it burns to create dihalides magnesium chloride, MgCl2 and magnesium bromide.

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What is the difference between atom and it’s ion ?
Sati [7]
Answer:
D. Number of electrons
8 0
3 years ago
Orbitals which are equal in energy are referred to as ________.
mash [69]

Degenerate Orbitals

~ Meaning ~

Electron orbitals that have the same energy levels are called degenerate orbitals. When assigning electrons to orbitals in determining electron configurations, the Aufbau principle states that lower energy orbitals are filled before higher energy orbitals.

8 0
3 years ago
The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal: CO(g) + H2O(g)
taurus [48]

<u>Answer:</u> The concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

<u>Explanation:</u>

For the given chemical reaction:

CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

The expression of K_c for above reaction follows:

K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}         ........(1)

We are given:

[CO]_{eq}=[H_2O]_{eq}=[H_2]_{eq}=0.10M

[CO_2]_{eq}=0.40M

Putting values in above equation, we get:

K_c=\frac{0.40\times 0.10}{010\times 0.10}\\\\K_c=4

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of hydrogen gas = 0.30 mol

Volume of solution = 2.0 L

Putting values in above equation, we get:

\text{Molarity of }H_2=\frac{0.30mol}{2L}=0.15M

When hydrogen gas is added, the concentration of product gets increased. But, by Le-Chatelier's principle, the equilibrium will shift in the direction where concentration of product must decrease, which is in the backward direction.

Concentration of hydrogen gas when equilibrium is re-established = 0.1 + 0.15 = 0.25 M

Now, the equilibrium is shifting to the reactant side. The equation follows:

                      CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial:              0.1      0.1                 0.4       0.1

At eqllm:       0.1+x   0.1+x           0.4-x      0.25-x

Putting values in expression 1, we get:

4=\frac{(0.25-x)(0.4-x)}{(0.1+x)(0.1+x)}\\\\3x^2+1.45x-0.06=0\\\\x=0.038,-0.522

Neglecting the negative value of 'x'

Calculating the concentrations of the species:

Concentration of carbon dioxide = (0.4 - x) = (0.4 - 0.038) = 0.362 M

Concentration of hydrogen gas = (0.25 - x) = (0.25 - 0.038) = 0.212 M

Concentration of carbon monoxide = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Concentration of water = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Hence, the concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

8 0
4 years ago
A 200.0-mL sample of helium gas is in a cylinder with a movable piston at 110 kPa and 275 K. The piston is pushed in until the s
Nutka1998 [239]

Answer:

P₂ = 261 KPa

Explanation:

Given data:

Volume of sample = 200 mL

Initial pressure = 110 KPa

Initial temperature = 275 K

Final volume = 95 mL

Final temperature = 310 K

Final pressure = ?

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₂ = P₁V₁T₂ /T₁ V₂

P₂ = 110 KPa× 200 mL× 310 K /275 K  × 95 mL

P₂ = 6820000 KPa / 26125

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3 0
3 years ago
What would you use if you needed to measure the volume of an object?
tangare [24]
Are there any answer choices?

4 0
3 years ago
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