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Shkiper50 [21]
3 years ago
12

What is the value of x in the equation below? 4(x + 3) = 9x + 16 + 3x

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

x = -1/2

Step-by-step explanation:

4(x + 3) = 9x + 16 + 3x

Distribute the 4

4x +12 = 9x+16+3x

Combine like terms

4x+12 = 12x+16

Subtract 4x

4x-4x+12 = 12x-4x+16

12 = 8x+16

Subtract 16

12-16 = 8x+16-16

-4 =8x

Divide by 8

-4/8 =8x/8

-1/2 =x

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Step-by-step explanation:

8 0
3 years ago
Explain whether each function is exponential <br> f(x)=2x^10
Elden [556K]

Answer:

42

Step-by-step explanation:

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3 years ago
Find the total mass of the triangular region shown below. All lengths are in cm, and the density of the region is sigma(x) = 1 +
anastassius [24]

Answer:

3 grams

Step-by-step explanation:

We are going to take the mass of a bunch of little strips below the triangle "roof." To do this, we must figure out what formula for the mass we'll use, in this case, we'll use:

Mass of strip = denisty * area = (1+x)*y*deltax grams

now, because the "roof" of the triangle contains two different integrals (it completely changes direction), we will use TWO integrals!

**pretend ∈ is the sum symbol

Mass of left part = lim x->0 ∈ (1+x)*y*deltax = inegral -1 to 0 of (1+x)*3*(x+1) = 3 * integral -1 to 0 of (x^2 + 2x + 1) = 3 *  1/3 = 1

Mass of left part = lim x->0 ∈ (1+x)*y*deltax = inegral 0 to 1 of (1+x)*3*(-x+1) = 3 * integral 0 to 1 of (-x^2 + 1) = 3 * 2/3 = 2

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8 0
3 years ago
What is the total surface area of the square pyramid?​
sleet_krkn [62]

Answer: Hello Luv......

380  (There is no picture i'm sorry,)

Step-by-step explanation:

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6 0
3 years ago
I need answers asap... please
aleksandrvk [35]

Answer:

see explanation

Step-by-step explanation:

(4)

consider the left side

factor the numerator

cosx - cos³x = cosx(1 - cos²x)

\frac{cosx(1-cos^2x)}{sinx}[/tex = [tex]\frac{cosxsin^2x}{sinx}

cancel sinx on numerator/denominator

= cosxsinx =right side ⇒ verified

(5)

Consider the left side

expand the factors

(1 + cotΘ)² + (1 - cotΘ)²

= 1 + 2cotΘ + cot²Θ + 1 - 2cotΘ + cot²Θ

= 2 + 2cot²Θ

= 2(1 + cot²Θ) ← 1 + cot²Θ = cosec²Θ

= 2cosec²Θ = right side ⇒ verified

(6)

Consider the left side

the denominator simplifies to

cosxtanx = cosx × \frac{sinx}{cosx} = sinx

\frac{sin^2x(secx+cosecx)}{sinx}

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= \frac{sinx}{cosx} + \frac{sinx}{sinx}

= tanx + 1 = right side ⇒ verified











3 0
3 years ago
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