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Maksim231197 [3]

3 years ago

6

The field-line representation of the e-field in a certain region in space is shown below. The dashed lines represent equipotenti

al lines.

1 answer:

lorasvet [3.4K]3 years ago

3 0

You need to go on google an dlook this up

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What is the string theory.

Leno4ka [110]

String the·o·ry
noun
a cosmological theory based on the existence of cosmic strings.

7 0

3 years ago

Read 2 more answers

An object of mass 6.00 kg falls with an aceleration of 8.00 m/s2. The magnitude of air resitance must be ____ N

allsm [11]

Using Newton's Second Law, we can find the air resistance. We know the net force is equal to mass times acceleration. $F_{net} = m*a = (6.00kg)(8.00 \frac{m}{s^2}) = 48N 

F_{g} - F_{d} = 48N

48N = (6.00kg)(9.81m/s^2) - F_{d} 

F_{d} = 10.86N$

7 0

3 years ago

Two positive charges of 6 µC are separated by a distance of 50 cm in air. What is the electric field strength at the midpoint of

attashe74 [19]

Answer:

The electric field strength at the midpoint of the line joining the charges is zero (0)

Explanation:

Given that the two charges are both positive (same charge) and are equal in magnitude that is 6uC. The electric field strength at the midpoint of the line joining the two charges will be equal and opposite in magnitude, therefore they will cancel each other out and the electric field strength at this point will be equal to zero.

4 0

3 years ago

The chain of length L and mass per unit length rho is released from rest on the smooth horizontal surface with a negligibly smal

devlian [24]

Answer:

Part a)

$a = \frac{x}{L} g$

Part b)

$T = \rho x g(1 - \frac{x}{L})$

Part c)

$v = \sqrt{gL}$

Explanation:

Part a)

Net pulling force on the chain is due to weight of the part of the chain which is over hanging

So we know that mass of overhanging part of chain is given as

$m = \rho x$

now net pulling force on the chain is given as

$F = \rho x g$

now acceleration is given as

$F = Ma$

$\rho x g = \rho L a$

$a = \frac{x}{L} g$

Part b)

Tension force in the part of the chain is given as

$mg - T = ma$

$\rho x g - T = \rho x a$

$\rho x(g - a) = T$

$\rho x (g - \frac{x}{L} g) = T$

$T = \rho x g(1 - \frac{x}{L})$

Part c)

velocity of the last link of the chain is given as

$a = \frac{x}{L} g$

$v\frac{dv}{dx} = \frac{x}{L} g$

now integrate both sides

$\int v dv = \frac{g}{L} \int x dx$

$\frac{v^2}{2} = \frac{gL}{2}$

$v = \sqrt{gL}$

3 0

3 years ago

How many kWh of energy does a 550-W toaster use in the morning if it is in operation for a total of 5.0 min? At a cost of 9.0 ce

iren [92.7K]

Answer:

0.0458 kWh

6.5736 cents

Explanation:

The formula for electric energy is given as

E = Pt................. Equation 1

Where E = Electric energy, P = Electric power, t = time.

Given; P = 550 W, t = 5 min = (5/60) h = 0.083 h.

Substituting into equation 1

E = 550(0.083)

E = 45.83 Wh

E = (45.83/1000) kWh

E = 0.0458 kWh.

Hence the kWh = 0.0458 kWh.

If the makes a toast four morning per week, and the are Four weeks in a month.

Total number days he makes toast in a month = 4×4 = 16 days.

t = 16×0.083 h = 1.328 h.

Total energy used in a month = 550(1.328)

E = 730.4 Wh

E = 0.7304 kWh.

If the cost of energy is 9.0 cents per kWh,

Then for 0.7304 kWh the cost will be 9.0(0.7304) = 6.5736 cents.

Hence this would add 6.5736 cents to his monthly electric bill

3 0

3 years ago