3 years ago

Can anyone plz help me

Physics

1 answer:

Alekssandra [29.7K]3 years ago

3 0

Answer:

1.) volume = 8 cm^3

2.) density = 2.6 g/cm^3

Explanation:

1.) volume =

$side {}^{3}$

=》

${2}^{3}$

=》

$8 \: cm {}^{3}$

2.) density =

$\frac{mass}{volume}$

=》

$\frac{20.8}{8}$

=》

$2.6 \: g \: cm {}^{ - 3}$

density = 2.6

You might be interested in

Approximately how old is the earth?

Wewaii [24]

<span>C) 4.5 billion years old</span>

6 0

3 years ago

With what force will a car hit a tree if the car has a mass of 3,550 kg and it is accelerating at a rate of 2.5 m/s2 on a snowy

bekas [8.4K]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3550 × 2.5

We have the final answer as

Hope this helps you

3 0

3 years ago

"On a good day, it takes Mr. Hess 23 minutes (1380 seconds) to drive the 12 miles (19,300 meters). What is his average velocity

il63 [147K]

Answer:

his average velocity is

$v = \frac{19300}{1380} = 13.9855(m \div s)$

5 0

3 years ago

2. This diagram represents a top-down view of an experiment on a table. The 250 g and 100 g masses are falling and are pulling t

Rasek [7]

Answer:

According to the data given in the question, experiment on table two pulling and falling masses are arranged in the fig. 250 g is pulling right side and 100 g pulling down. The gravitational force is common to both the masses, so we cannot say that the block moves towards heavier mass, also the block does not move towards the lighter mass.

Obviously, the effect of heavier mass of 250 g is more on the block, so the block moves towards right bottom corner. i.e., diagonally between two masses

please find the attachment.

4 0

3 years ago

Read 2 more answers

Calculate the magnitude and direction of the electric field 2.0 m from a long wire that is charged uniformly at λ = 4.0 × 10-6 C

Len [333]

Answer: 71.93 *10^3 N/C

Explanation: In order to calculate the electric field from long wire we have to use the Gaussian law, this is:

∫E*dr=Q inside/εo Q inside is given by: λ*L then,

E*2*π*r*L=λ*L/εo

E= λ/(2*π*εo*r)= 4* 10^-6/(2*3.1415*8.85*10^-12*2 )= 71.93 * 10^3 N/C

6 0

3 years ago

Can anyone plz help me ​

Can anyone plz help me