The first step in deforestation in the Amazon is _______. A. Logging b. Farming c. Ranching d. Road building.

If you burn 46.0 g of hydrogen and produce 411 g of water, how much oxygen reacted?

g100num [7]

The answer is 365 grams because you need to subtract 411 by 46.

3 0

3 years ago

A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o

statuscvo [17]

Answer: The value of $K_{eq}$ is 0.044

Explanation:

We are given:

Initial moles of methane = $4.10\times 10^{-2}mol=0.0410moles$

Initial moles of carbon tetrachloride = $6.51\times 10^{-2}mol=0.0651moles$

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

$\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}$

So, concentration of methane = $\frac{0.0410}{1.00}=0.0410M$

Concentration of carbon tetrachloride = $\frac{0.0651}{1.00}=0.0651M$

The given chemical equation follows:

$CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)$

Initial: 0.0410 0.0651

At eqllm: 0.0410-x 0.0651-x 2x

We are given:

Equilibrium concentration of carbon tetrachloride = $6.02\times 10^{-2}M=0.0602M$

Evaluating the value of 'x', we get:

$\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M$

Now, equilibrium concentration of methane = $0.0410-x=[0.0410-0.0049]=0.0361M$

Equilibrium concentration of $CH_2Cl_2=2x=[2\times 0.0049]=0.0098M$

The expression of $K_{eq}$ for the above reaction follows:

$K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}$

Putting values in above expression, we get:

$K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044$

Hence, the value of $K_{eq}$ is 0.044

8 0

3 years ago

What did the scientists have to consider before releasing the dragonflies into the wild? Why?

pentagon [3]

Maybe they had to consider the habitat to make sure the habitat they were releasing the dragonflies into would be appropriate for the dragonflies.

3 0

3 years ago

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Micah is investigating the transformation between potential and kinetic energy within a system. He uses a swinging pendulum in h

slega [8]

Answer: The total energy is maintained as energy transformed

Explanation:

The kinetic energy and potential energy is been maintained as each of the experiment is been performed which is 50Joules

5 0

3 years ago

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What is the molecular formula of an empirical N2H3 if n=2? SHOW WORK!

aliya0001 [1]

A compound's empirical formula tells you what the smallest whole number ratio between the atoms that make up that compound is.

I think of the empirical formula as a building block for molecules. A compound's molecular formula will depend on how many building blocks are needed to build a molecule of a given substance.

In your example, you know that the empirical formula of the compound is

NO

2

.

This tells you that the minimum ratio between nitrogen atoms and oxygen atoms is

1

:

2

. In other words, the molecular formula will be a multiple of this building block.

molecular formula

=

empirical formula

×

n

, where

n

- the number of building blocks needed to build the molecular formula.

You also know that the molar mass of your compound is

92 g/mol

.

This means that the molar mass of all the atoms that make up that molecule must add up to give

92 g/mol

.

So, how would you determine how many building blocks you need? Well, start by figuring out the molar mass of one building block, i.e. the molar mass of the empirical formula.

Since it contains one nitrogen atom and two oxygen atoms, you will get

1

×

14.0067 g/mol

+

2

×

15.9994 g/mol

=

46.0055 g/mol

So, if one building block has a molar mass of

46.0055 g/mol

, how many would you need to get the molecule?

46.0055 g/mol

⋅

n

=

92 g/mol

n

=

92

g/mol

46.0055

g/mol

=

1.99976

≈

2

This means that the compound's molecular formula, which lists all the atoms that make up a molecule, will be

(

NO

2

)

×

2

=

N

2

O

4

→

dinitrogen tetroxide

7 0

2 years ago

Read 2 more answers