Answer:
1. Get the mass of each element by assuming a certain overall mass for the sample (100 g is a good mass to assume when working with percentages). ...
2. Convert the mass of each element to moles. ...
3. Find the ratio of the moles of each element. ..
4. Use the mole ratio to write the empirical fomula
<h2>
1.25 g of
would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
</h2>
Explanation:
To calculate the number of moles for given molarity, we use the equation:


According to stoichiometry:
1 mole of
will give = 1 mole of 
0.0208 moles of
will give =
of 
Mass of 
Thus 1.25 g of
would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
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Nitrogen and oxygen are in unpolluted air
Answer: The answer to this question is transpiration.
Explanation: I know this answer because i looked it up in a book. The other explanation is I study about this a lot.