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Dahasolnce [82]
3 years ago
10

How many moles of CO2 must dissolve in excess water to produce 12 moles of H2CO3?

Chemistry
1 answer:
vodka [1.7K]3 years ago
3 0

Answer:

12 moles of CO₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CO₂ + H₂O —> H₂CO₃

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Finally, we shall determine the number of moles of CO₂ that will dissolve in water to produce 12 moles of H₂CO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Therefore, 12 moles of CO₂ will also dissolve in water to produce 12 moles of H₂CO₃.

Thus, 12 moles of CO₂ is required.

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Answer is: 2,469 mL give to the child.
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m(Medrol) = 32,93 kg · 1,5 mg/kg.
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d(Medrol) = 20,0 mg/mL.
V(Medrol) = m(Medrol) ÷ d(Medrol).
V(Medrol) = 49,39 mg ÷ 20 mg/mL.
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8 0
3 years ago
Which substance is needed in order for this biochemical reaction to occur?
Anna35 [415]
What biochemical reaction??
4 0
3 years ago
2KClO3 2KCl + 3O2
FinnZ [79.3K]
True, because most chemical reactions have more moles but not really.
Also that they decompose better. "not really"
4 0
3 years ago
Find the mole fraction of benzene and toluene in solution containing​
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Answer:

The mole fraction of benzene and toluene in solution containing mole fraction of benzene and toluene in solution containing is 45.9%

Explanation:

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5 0
3 years ago
A goldsmith melts 12.4 grams of gold to make a ring. The temperature of the gold rises from 26°C to 1064°C, and then the gold me
DiKsa [7]

Problem One

You will use both m * c * deltaT and H = m * heat of fusion.

Givens

m = 12.4 grams

c = 0.1291

t1 = 26oC

t2 = 1204

heat of fusion (H_f) = 63.5 J/grams.

Equation

H = m * c * deltaT + m * H_f

Solution

H = 12.4 * 0.1291 * (1063 - 26) + 12.4 * 63.5

H = 1660.1 + 787.4

H = 2447.5 or 2447.47 is the exact answer. I have to leave the rounding to you. I have no idea where to round it although I suspect 2450 would be right for 3 sig digs.

Problem Two

Formula and Givens

t1 = 14.5

t2 = 50.0

E = 5680

c = 4.186

m = ??

E = m c * deltaT

Solution

5680 = m * 4.186 * (50 - 14.5)

5680 = m * 4.186 * (35.5)

5680 = m * 148.603 * m

m = 5680 / 148.603

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m = 38.2 to 3 sig digs.

8 0
3 years ago
Read 2 more answers
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