Question

A traffic controller at the airport watches a commercial plane circling above at a distance of 24.0 km as the pilot waits for clearance to land. If the Moon subtends an angle of 9.89 10-3 radians at the controller's location, what is the distance the jet travels as its nose moves across the diameter of the Moon?

Answer 1

Answer:

The distance travelled is $S = 237.36 \ m$

Explanation:

From the question we are told that

    The distance of the airplane from the ground is  $L = 24.0\ km$

     The angle subtended by the moon is $\theta = 9.89*10^{-3} \ radians$

The distance traveled can be mathematically represented as

            $S = R \theta$

Substituting values

            $S = 24 *10^3 * 9.89*10^{-3}$

           $S = 237.36 \ m$