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Alex787 [66]
3 years ago
10

Draw a simple picture of your foot kicking a

Physics
1 answer:
Anton [14]3 years ago
8 0
The force is going which ever way the person kicks the ball.

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On a frictionless air track, cart A hits cart B moving at a velocity of 2 meters per second to the right. Which answer predicts
qaws [65]

Answer:

Cart A will bounce to the left while cart B will move right at less than 2 meters per second

Explanation:

4 0
3 years ago
Read the scenario below and answer the question that follows.
IceJOKER [234]
I think it is a because she cries when she sees them
5 0
3 years ago
What is the mass of an object that experiences an acceleration of 5m/s^2 when a force of 500N acts on it?
earnstyle [38]
Data;
m (mass) = ?
a (acceleration) = 5 m/s²
F (force) = 500 N

Formula:
F = m * a

Solving:
F = m*a
500 = m*5
500 = 5m
5m = 500
m =  \frac{500}{5}
\boxed{\boxed{m = 100\:Kg}}

Answer:
<span>The mass of an object you are experimenting with is 100 kg</span>
3 0
3 years ago
If the 3rd harmonic has a frequency of 600Hz, the frequency of the fundamental is ____________?
castortr0y [4]

Answer:

Fundamental frequency is 200 Hz.

Explanation:

It is given that,

Frequency of the 3rd harmonic is 600 Hz.

Let f is the fundamental frequency. We need to find the value of f. The frequency of third harmonic is given by :

3f=600\ Hz

So, fundamental frequency f is equal to :

f = 200 Hz

So, the fundamental frequency of the harmonics is 200 Hz. Hence, this is the required solution.

4 0
4 years ago
Unpolarized light of intensity 0.0288 W/m2 is incident on a single polarizing sheet. What is the rms value of the electric field
galina1969 [7]

Answer:

the rms value of the electric field component transmitted is 3.295 V/m

Explanation:

Given;

intensity of the unpolarized light, I = 0.0288 W/m²

For unpolarized light, the relationship between the amplitude electric field and intensity is given as;

E_{max} = \sqrt{2\mu_0cI} \\\\E_{max} = \sqrt{2(4\pi \times 10^{-7})(3\times 10^8)(0.0288)} \\\\E_{max} = 4.66 \ V/m

The relationship between the rms value of the electric field and the amplitude electric field is given as;

E_{rms} = \frac{E_0}{\sqrt{2} } =\frac{E_{max}}{\sqrt{2} }  \\\\E_{rms} = \frac{4.66}{\sqrt{2} }\\\\E_{rms} = 3.295 \ V/m

Therefore, the rms value of the electric field component transmitted is 3.295 V/m

5 0
3 years ago
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