Answer:
![\mu = 1.645](https://tex.z-dn.net/?f=%5Cmu%20%3D%201.645%20)
Explanation:
By Snell's law we know at the left surface
![\theta_i = 19^o](https://tex.z-dn.net/?f=%5Ctheta_i%20%3D%2019%5Eo)
![\theta_r = ?](https://tex.z-dn.net/?f=%5Ctheta_r%20%3D%20%3F)
![\mu_1 = 1](https://tex.z-dn.net/?f=%5Cmu_1%20%3D%201)
![\mu_2 = \mu](https://tex.z-dn.net/?f=%5Cmu_2%20%3D%20%5Cmu)
now we have
![1 sin19 = \mu sin\theta_r](https://tex.z-dn.net/?f=1%20sin19%20%3D%20%5Cmu%20sin%5Ctheta_r)
![0.33 = \mu sin\theta_r](https://tex.z-dn.net/?f=0.33%20%3D%20%5Cmu%20sin%5Ctheta_r)
now on the other surface we know that
angle of incidence = ![\theta_r'](https://tex.z-dn.net/?f=%5Ctheta_r%27)
![\theta_e = 90](https://tex.z-dn.net/?f=%5Ctheta_e%20%3D%2090%20)
so again we have
![\mu sin\theta_r' = 1 sin90](https://tex.z-dn.net/?f=%5Cmu%20sin%5Ctheta_r%27%20%3D%201%20sin90)
so we have
![\theta_r = sin^{-1}\frac{0.33}{\mu}](https://tex.z-dn.net/?f=%5Ctheta_r%20%3D%20sin%5E%7B-1%7D%5Cfrac%7B0.33%7D%7B%5Cmu%7D)
![\theta_r' = sin^{-1}\frac{1}{\mu}](https://tex.z-dn.net/?f=%5Ctheta_r%27%20%3D%20sin%5E%7B-1%7D%5Cfrac%7B1%7D%7B%5Cmu%7D)
also we know that
![\theta_r + \theta_r' = 49](https://tex.z-dn.net/?f=%5Ctheta_r%20%2B%20%5Ctheta_r%27%20%3D%2049)
![sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Cfrac%7B0.33%7D%7B%5Cmu%7D%20%2B%20sin%5E%7B-1%7D%5Cfrac%7B1%7D%7B%5Cmu%7D%20%3D%2049)
By solving above equation we have
![\mu = 1.645](https://tex.z-dn.net/?f=%5Cmu%20%3D%201.645%20)
Answer:
60kgm/s
Explanation:
Given parameters:
Mass of frisbee = 5kg
Final speed = 12m/s
Unknown:
Impulse of the frisbee = ?
Solution:
The impulse of the frisbee is the same as the change in momentum.
It is given as:
Impulse = mass (Final velocity - Initial velocity)
Impulse = 5(12 - 0) = 60kgm/s
Answer:
trees
Explanation:
referring to the tree to prove his/her point.
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