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Nikitich [7]
3 years ago
15

Thomas had a volume of 8.5 g of sodium chloride. What is the molar mass.?

Chemistry
1 answer:
alina1380 [7]3 years ago
5 0

Answer:

58.44 g/mol

Explanation:

In this problem, make sure to remember that volume is measured in mL, L or any other units of volume. Remember that g represents grams, and grams is a measure of mass.

However, independent of what mass or what volume we take, molar mass is known to be an intensive property. That is, molar mass doesn't depend on any external conditions or any measurements.

Molar mass solely depends on the chemical structure of a compound and is a constant number at any given conditions.

In this problem, we are given sodium chloride, NaCl. In order to find its molar mass, we need to refer to the periodic table, find the atomic masses of Na and Cl and then add them up to have the molar mass of NaCl:

M_{NaCl} = M_{Na} + M_{Cl} = 22.99 g/mol + 35.453 g/mol = 58.44 g/mol

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saveliy_v [14]

Answer:

b. colloid

Explanation:

Colloids are solutions that are going to have a solute and a solvent, but the size of the particles are bigger than in a solution that is clear. that is the reason that it looks blurred because the particles are bigger.

In the other hand, these particles of the solute are big, but not so big and heavy as in a suspension, so they are not going to precipitate in the bottom.

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3 0
3 years ago
Based on the periodic table why are be, bg, ca and sr in the same column/group/family?
Lesechka [4]

Answer:

The elements are in the same column/group IIA.

See the explanation below, please.

Explanation:

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7 0
3 years ago
calculate the number of moles of sulfuric acid that is contained in 250 mL of 8.500 M sulfuric acid solution
san4es73 [151]

Answer : The moles of H_2SO_4 are, 2.125 mole.

Explanation : Given,

Molarity of H_2SO_4 = 8.500 M

Volume of solution = 250 mL  = 0.250 L    (1 L = 1000 mL)

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of }H_2SO_4}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

8.500M=\frac{\text{Moles of }H_2SO_4}{0.250L}

\text{Moles of }H_2SO_4=2.125mol

Therefore, the moles of H_2SO_4 are, 2.125 mole.

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