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Vinvika [58]
3 years ago
5

Give the chemical formulas for (a) silicon tetrabromide, (b) disulfur dichloride, (c) diphosphorus hexaoxide.

Chemistry
1 answer:
sdas [7]3 years ago
6 0

Answer:

(a)

SiBr_4

(b)

S_2Cl_2

(c)

P_2O_6

Explanation:

(a)

The given compound is silicon tetrabromide. It means that 1 silicon and four bromine atoms are combined to form the molecule.

The chemical formula of silicon tetrabromide is SiBr_4

(b)

The given compound is disulfur dichloride. It means that 2 sulfur atoms and 2 chlorine atoms are combined to form the molecule.

The chemical formula of disulfur dichloride is S_2Cl_2

(c)

The given compound is diphosphorus hexaoxide. It means that 2 phosphorus atoms and 6 oxygen atoms are combined to form the molecule.

The chemical formula of diphosphorus hexaoxide is P_2O_6

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Determine the percent water in MgSO4*7H20?
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Answer:

\% H_2O=51.2\%

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol

Thus, the percent water is:

\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\

So we plug in to obtain:

\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%

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2 years ago
2. How many molecules are contained in 25 L of N₂ at S. T.P.?
irina [24]

Explanation:

How many nitrogen molecules are in 1 liter of nitrogen gas at STP?

Answer

2

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Pete Gannett

 · 

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Ph.D. Chemistry, University of Wisconsin-Madison, (1982)2y

Seems to be an ideal gas law question. The relevant equation is:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles of gas, R is the gas constant (0.082 atm-L/mole-deg K), and T is temperature in Kelvins. STP means standard temperature and pressure and this is taken as 1 atm and 0º C or 273 K.

To calculate the number of molecules we will use the constant 6.023 * 10^23 molecules/mole and, therefore, we will need to know the number of moles (n). So, first we’ll rearrange the gas law equation, isolating ’n’ and then put the numbers in.

n = PV/RT = 1 * 1 / (0.082)(273) = 0.0447 moles

So, to calculate the number of molecules, multiple this by the number of molecules in a mole and you get:

# molecules of nitrogen in 1 Liter at STP = 6.023 * 10^23 molecules/mole * 0.0447 moles = 2.6905 * 10^22 molecules

Note, it does not matter what the gas is.

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