Answer:
12 molecules of carbon dioxide
24 molecules of water
Explanation:
Given parameters:
Number of molecules of methane = 12 molecules
Unknown:
Number of molecules of carbon dioxide = ?
Number of molecules of water = ?
Solution:
The given amount of methane is the limiting reagent in this reaction. By this, we can ascertain the amount of products that will be formed and the extent of the reaction.
We first write the balanced chemical equation for this reaction;
CH₄ + 2O₂ → CO₂ + 2H₂O
From balanced equation;
1 mole of methane produced 1 mole of carbon dioxide
12 molecules of methane will produce 12 molecules of carbon dioxide
Also;
1 mole of methane produced 2 moles of water;
12 molecules of methane will produce (12 x 2)molecules = 24 molecules of water
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To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:
P1V1 = P2V2,
Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:
(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr
The final pressure exerted by the gas would be 0.593 torr.
Hope this helps!
