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Gwar [14]
3 years ago
10

A 20.0 ml sample of glycerol has a mass of 25.1 grams. what is the density of glycerol in ounces/quart? (1.00 ounce = 28.4 grams

, and 1.00 liter = 1.06 quarts)
Chemistry
1 answer:
san4es73 [151]3 years ago
8 0
If 1ounce= 28.4g
then xounce=25.1g
cross multiply to satisfy x
28.4x=25.1    divide both sides by 28.4
x=25.1/28.4
x=0.88 ounce
if 1 litre=1.06 quarts 
then 0.02l=x quarts
x =0.212 quarts
so density =mass/volume
 density=0.88/0.212
density=4.15 ounces/quarts
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Balance the following equation:
Firdavs [7]

Answer: a) 2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

b) 1 mole of SO_2 is produced.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The skeletal equation is:

K_2CrO_4+Na_2SO_3+HCl\rightarrow KCl+Na_2SO_4+CrCl_3 +H_2O

The balanced equation will be:

2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

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Reduction: SO_4^{2-}+2e^-+4H^+\rightarrow SO_2+2H_2O

Net reaction:  2I-^-+SO_4^{2-}+4H^+\rightarrow I_2+SO_2+2H_2O

When 1 mole of I_2 is produced, 1 mole of SO_2 is produced.

8 0
3 years ago
Balancing chemical equations!<br> need help!!!<br> don’t mind how i wrote it.
elena-s [515]

Answer:

2 KCIO₃ → 2 KCI + 3 O₂

Explanation:

A chemical equation is balanced when the number of atoms of each element is equal on both sides of the equation.

You have already identified the initial number of atoms of each element on both sides of the equation. As a rule of thumb, we balance the number of oxygen and hydrogen atoms last.

However, since all the other elements are already balanced, we shall start by balancing the number of oxygen atoms.

The lowest common multiple of 2 and 3 is 6. Thus, we shall ensure that both sides of the equation has 6 oxygen atoms.

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C--- 2

I --- 2

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K --- 1

C --- 1

I --- 1

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<u>Reactants</u>

K --- 2

C --- 2

I --- 2

O --- 6

<u>Products</u>

K --- 2

C --- 2

I --- 2

O --- 6

The equation is now balanced.

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\huge\red{ \mid{ \underline{ \overline{ \tt  ♡ FORMULA: ♡ }} \mid}}

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{\huge\pink{\fbox{{࿐REACTION࿐}}}}

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6 0
3 years ago
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