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aev [14]
3 years ago
7

PLEASE HELP, I'M BEGGING YOU!

Chemistry
1 answer:
Sloan [31]3 years ago
6 0
Can I see a picture please so i can answer your question
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Which of the following is compound?
asambeis [7]

Answer:

fire

Explanation:

Fire is made up of many different substances, so it is not an element. ... Flames are the result of a chemical reaction, primarily between oxygen in the air and a fuel, such as wood or propane. In addition to other products, the reaction produces carbon dioxide, steam, light, and heat

4 0
3 years ago
Read 2 more answers
a solution of iron 3 sulfate and a solution of lead 2 perchlorate react to produce lead 2 sulfate precipitate
777dan777 [17]

Balanced equation :

Fe2(SO4)3 + 3Pb(ClO4)2 → 2Fe(ClO4)3 + 3PbSO4

<h3>Further explanation</h3>

Given

Word equation

Required

Balanced equation

Solution

Chemical equations can be expressed in terms of:

  • word equation
  • skeleton equation
  • balanced equation

Word equation :

a solution of iron 3 sulfate and a solution of lead 2 perchlorate react to produce lead 2 sulfate precipitate

Skeleton equation :

Fe2(SO4)3 + Pb(ClO4)2  → Fe(ClO4)3 + PbSO4

Balanced equation :

Fe2(SO4)3 + 3Pb(ClO4)2 → 2Fe(ClO4)3 + 3PbSO4

7 0
2 years ago
Which phrases describe all the outer planets' motion? Check all that apply.
viktelen [127]
  1. answer:fast rotation. 2. explanation: I choose this as my answer because when the outer planets orbit it move faster
3 0
2 years ago
Alice and Marge are studying the properties of matter. The girls cut some silver-colored magnesium sheets into 3-inch long strip
frosja888 [35]
<span>B) Magnesium reacts in acids</span>
4 0
2 years ago
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The pH of a 0.65M solution of hydrofluoric acid HF is measured to be 1.68. Calculate the acid dissociation constant Ka of hydrof
sergey [27]

Answer:

Kₐ = 6.7 x 10⁻⁴

Explanation:

First lets write the equilibrium expression, Ka , for the dissociation of hydrofluoric acid:

HF + H₂O     ⇄   H₃O⁺ +   F⁻

Kₐ = [ H₃O⁺ ] [ F⁻ ] /[ [ HF ]

Since we are given the pH we can calculate the  [ H₃O⁺ ]  ( pH = - log [ H₃O⁺ ] , and because the acid dissociates into a 1: 1  relation , we will also have [F⁻ ]. The  [ HF ] is given in the question so we have all the information that is needed to  compute Kₐ.

pH = -log [ H₃O⁺ ]

1.68 = - log [ H₃O⁺ ]

Taking antilog to both sides of this equation:

10^-1.68 = [ H₃O⁺ ] ⇒ 2.1 X 10⁻²  M= [ H₃O⁺ ]

[ F⁻ ] = 2.1 X 10⁻² M

Solving for Kₐ :

Kₐ = ( 2.1 X 10⁻² ) x  ( 2.1 X 10⁻² ) / 0.65 = 6.7 x 10⁻⁴  

(Rounded to two significant figures, the powers of 10 have infinite precision )

4 0
2 years ago
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