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strojnjashka [21]
2 years ago
11

You are presented with a mystery as part of your practical experiment. You have a solution of Pb(NO3)2

Chemistry
1 answer:
shusha [124]2 years ago
7 0
Ho123 right I’m sorry of I’m wrong
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3 years ago
A certain liquid X has a normal boiling point of 133.60°C and a boiling point elevation constant Kb= 2.46°C kg mol^-1.Calculate
Afina-wow [57]

Answer:

136.63 °C

Explanation:

ΔTb=Tb solution - Tb pure

Where; Tb pure = 133.60°C

molar mass of solute = 121.14 g/mol

number of moles of solute; 52.2g/121.14 g/mol = 0.431 moles

molality = 0.431 moles/350 * 10^-3 = 1.23 molal

Then;

ΔTb = Kb * m * i

Kb = 2.46°C kg mol^-1

m = 1.23 molal

i = 1

ΔTb = 2.46 * 1.23 * 1

ΔTb = 3.03 °C

Hence;

Tb solution = ΔTb + Tb pure

Tb solution = 3.03 °C + 133.60°C

Tb solution = 136.63 °C

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2 years ago
If two metals has the same specific heat how can distinguish them in two ways​
tensa zangetsu [6.8K]

Explanation:

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How many miles of H2O are produced when 0.322 mol of octane is burned?
victus00 [196]

Answer:

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Answer:

Neon (Ne)

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I got u

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