The balanced reaction equations are;
a) 4 NaClO + H2S → 4 NaCl + H2SO4
b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O
<h3>What is a balanced redox reaction?</h3>
A redox reaction is said to be balanced when the number of electrons gained is equal to the number of electrons lost.
Let us now write the balanced reaction equations one after the other. Thus;
a) 4 NaClO + H2S → 4 NaCl + H2SO4
b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O
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Answer:
The answer to your question is Aluminum
Explanation:
Number of clues
1.- If this element has 3 rings in its Bohr model, we are looking for and element located in the third period of the periodic table.
For example Sodium, Magnesium, Aluminum, Silicate, Phosphorus, Sulfur, Chlorine and, Argon.
2.- It makes three bonds to become stable, then we are looking for and element located in the third group like
Boron, Aluminum, Gallium, Indium, etc
Conclusion
The element that has both characteristics is Aluminum
One mole of Na2SO4 is 6.022 * 10^(23) molecules. We can divide this into the quantity in the question to find a value of 1.5/6.022 = 0.2491 moles. Rounded to two significant figures and put in scientific notation, we can rewrite this quantity as 2.5 * 10^(-1) moles
