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Scorpion4ik [409]
2 years ago
6

An engine flywheel initially rotates counterclockwise at 6.55 rotations/s. Then, during 20.9 s, its rotation rate changes to 2.1

9 rotations/s clockwise. Find the flywheel's average angular acceleration (including its sign) in radians per second squared. Define counterclockwise rotation as positive.
Physics
1 answer:
11Alexandr11 [23.1K]2 years ago
7 0

Answer:

The average angular acceleration is -2.628 rad/s²

Explanation:

Counterclockwise = positive

Clockwise = -negative

Given;

initial rotation of the flywheel, θ₁ = 6.55 rotation/s

final rotation of the flywheel, θ₂ = - 2.19 rotation/s

The average angular acceleration is given by;

\alpha = \frac{\delta \theta}{\delta t}\\\\ \alpha =\frac{\theta _2 - \theta_ 1}{t}\\\\ \alpha =\frac{-2.19 -6.55}{20.9} \\\\ \alpha =\frac{-8.74}{20.9}\\\\ \alpha = -0.4182 \ rotation / s^2\\\\ \alpha = \frac{-0.4182 \ rotation}{s^2}*\frac{2\pi \ radian}{rotation}\\\\ \alpha = -2.628 \ rad/s^2

Therefore, the average angular acceleration is -2.628 rad/s²

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Discussion:
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This voltage may also be calculated using capacitance and charge;

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Provided that the total charge is 'q', hence the total voltage can be expressed as:

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<h2>Answer:D</h2>

Explanation:

Option A:

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Option B:

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Option C:

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Option D:

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Answer:

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Explanation:

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Given:

Uniform distributed load with an intensity of W = 50 kN / m on an overhang beam.

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