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taurus [48]
3 years ago
8

a rocket initially at rest on the ground lifts off vertically with a constant acceleration of 2.0 x 10^1 meters per second^2. Ho

w long will it take the rocket to reach an altitude of 9.0 x 10^3 meters ?
Physics
1 answer:
xenn [34]3 years ago
7 0

Here's the formula for the distance covered by an accelerating body in some amount of time ' T '. This formula is incredibly simple but incredibly useful. It pops up so often in Physics that you really should memorize it:

D = 1/2 a T²

Distance = (1/2)·(acceleration)·(time²)

This question gives us the acceleration and the distance, and we want to find the time.

(9,000 m) = (1/2) (20 m/s²) (time²)

(9,000 m) = (10 m/s²) (time²)

Divide each side by 10 m/s²:

(9,000 m) / (10 m/s²) = (time²)

900 s² = time²

Square root each side:

<em>T = 30 seconds</em>

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How much work does a 65 kg person climbing a 2000 m high cliff do?
qaws [65]

The answer for the following question is explained below.

  • <u><em>Therefore the work done is 130 kilo Joules.</em></u>

Explanation:

Work:

A force causing the movement or displacement of an object.

Given:

mass of the person (m) = 65 kg

height of the cliff (h) = 2000 m

To calculate:

work done (W)

We know;

According to the formula:

  <u>W = m × g × h</u>

Where;

m represents mass of the person

g represents the acceleration due to gravity

where the value of g is;

  <u> g = 10 m/ s²</u>

h represents the height of the cliff

From the above formula;

  W = 65 × 10 × 2000

 W = 130,000 J

  W = 130 Kilo Joules

<u><em>Therefore the work done is 130 kilo Joules.</em></u>

3 0
3 years ago
Rosalinda’s take-home pay is 1700 a month she spends 11% of her take-home pay on her cable bill how much is Rosalinda’s monthly
Marizza181 [45]

Answer:

Explanation:

To solve this simply put 11% in its decimal form (0.11) and multiply it by her take-home pay and boom that's yer answer 187

6 0
3 years ago
How does the electric force between two charged particles change if particle's charge is reduced by a factor of 3?
MAVERICK [17]

The force between two charges is proportional to the product of the charges.

If only one of the charges is reduced by a factor of 3, then the force is reduced by a factor of 3.

If both charges are reduced by a factor of 3, then the force is reduced by a factor of 9.

3 0
4 years ago
Read 2 more answers
a length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be
Natali [406]
The equivalent resistance of n resistors connected in parallel is given by
\frac{1}{R_{eq}} =  \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n} (1)

In our problem, the resulting resistance of the 5 pieces connected in parallel is R_{Eq}=2.00 \Omega, and since the 5 pieces are identical, their resistance R is identical, so we can rewrite (1) as
\frac{1}{R_{Eq} }= \frac{1}{2 \Omega}= \frac{1}{R}+ \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   =  \frac{5}{R}
From which we find R= 5 \cdot 2 \Omega = 10 \Omega.

So, each piece of wire has a resistance of 10 \Omega. Before the wire was cut, the five pieces were connected as they were in series. The equivalent resistance of a series of n resistors is given by
R_{Eq}=R_1 + R_2 + ...+R_n
So if we apply it at our case, we have
R_{eq}=R+R+R+R+R=5 R= 5\cdot 10 \Omega= 50 \Omega

therefore, the resistance of the original wire was 50 \Omega.
5 0
3 years ago
Help me please I’m begging u!!
Yakvenalex [24]
The speed of a wave, c, is given by the length of the wave, λ, times the frequency (times per second a cycle passes).  Since frequency has units of inverse seconds, the units will then be m/s as we expect.
c= \lambda f=2m * 140Hz=280m/s
7 0
3 years ago
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