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taurus [48]
3 years ago
8

a rocket initially at rest on the ground lifts off vertically with a constant acceleration of 2.0 x 10^1 meters per second^2. Ho

w long will it take the rocket to reach an altitude of 9.0 x 10^3 meters ?
Physics
1 answer:
xenn [34]3 years ago
7 0

Here's the formula for the distance covered by an accelerating body in some amount of time ' T '. This formula is incredibly simple but incredibly useful. It pops up so often in Physics that you really should memorize it:

D = 1/2 a T²

Distance = (1/2)·(acceleration)·(time²)

This question gives us the acceleration and the distance, and we want to find the time.

(9,000 m) = (1/2) (20 m/s²) (time²)

(9,000 m) = (10 m/s²) (time²)

Divide each side by 10 m/s²:

(9,000 m) / (10 m/s²) = (time²)

900 s² = time²

Square root each side:

<em>T = 30 seconds</em>

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Answer:

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32.2Newton

Explanation:

To solve for the minimum force, let us assume it to be F (N)

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when a circular plate of metal is heated in an oven, its radius increases at .03 cm/min, at what rate is the area increasing whe
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Answer:

Rate of change of area will be 9.796cm^2/min

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\frac{dA}{dt}=2\times 3.14\times 52\times 0.03=9.796cm^2/min

So rate of change of area will be 9.796cm^2/min

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