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omeli [17]
3 years ago
11

2nd question!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

D.

Explanation:

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The acceleration due to gravity is
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Explanation:

To keep the rider from sliding down, then the friction force F_f must at least be equal to gravity force F_p

F_f = F_p

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where μ is the coefficient, N is the normal force acted by the rotating cylinder, m is the mass of a person and g = 9.81 m/s2 is the gravitational acceleration.

According to Newton's 3rd and 2nd laws, the normal force would be equal to the centripetal force F_c, which is the product of centripetal acceleration a_c and object mass m

N = F_c = a_cm

Therefore

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\mu a_c = g

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a_c = v^2/r = 15^2 / 3 = 75 m/s^2

Therefore

\mu = g/a_c = 9.81 / 75 = 0.1308

3 0
3 years ago
A force F= (6.70 N)i + (5.60 N)j + (6.60 N)k act on a 9.80 kg mobile object that moves from an initial position of di = (9.10 m)
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W = 0.11J

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Explanation:

Please see attachment below.

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