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NemiM [27]
3 years ago
14

Name the following compounds:

Chemistry
1 answer:
HACTEHA [7]3 years ago
3 0

CaF2 = Calcium fluoride (leave it as is, it in emoerical form already)

Na20 = Sodium oxide (leave it as is, it in emoerical form already)

BaS = Barium Sulfide (leave it as is, it in emoerical form already)

CuSO4 = Copper(II) sulfate = CuSO4 5H2O

Fe2O3 = Iron(III) oxide (leave it as is, it in emoerical form already)

HgCl2 = Mercury(II) chloride (leave it as is, it in emoerical form already)

KC2H3O2 = Potassium Acetate (leave it as is, it in emoerical form already)

Al(OH)3 = Aluminium hydroxide (leave it as is, it in emoerical form already)

Fe(NO3)3 = Iron(III) nitrate (leave it as is, it in emoerical form already)

N2O5 = Dinitrogen pentoxide = N2O5 (it's subscrip is already simplified)

PO5 = Phosphorus pentoxide = P2 O5 (there was just no 2 after the P so that's all that was needed there)

I'm am so sorry if this didn't help too much, I hope I did help, I in some way, have a wonderful day.

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Please help and explain!
Marianna [84]

Answer:

A: 53.346in

B. 7.62cm

C. 0.116km

D. 57000m

E. 9.82x10-⁸kg

G. 11.375lb

Explanation:

i don't know how to explain it to you

6 0
2 years ago
Find the zeros of the quadratic equation f(x)= 6x²-3, and verify the relation between its zeros and coefficients.
pishuonlain [190]

Answer:

f(x) = 6x²-3

f(x) = 0

6x²-3 = 0

6x² = 3

x² = 3/6

x² = 1/2

x = 1/√2 , -1/√2

Roots of f(x) = 1/√2 , -1/√2

Verification = (i) 6(1/√2)² - 3

= 6(1/2) - 3

= 3-3

= 0

(ii) 6(-1/√2)² - 3

= 6(1/2) - 3

= 3-3

= 0

5 0
3 years ago
Read 2 more answers
In a single displacement reaction between sodium phosphate and barium, how much of each product (in grams) will be formed from 1
weeeeeb [17]

Answer:

A. 3.36g of Na.

B. 14.62g of Ba3(PO4)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3Ba + 2Na3PO4 → 6Na + Ba3(PO4)2

Next, we shall determine the mass of Ba that reacted and the mass of Na and Ba3(PO4)2 produced from the equation.

This is illustrated below:

Molar Mass of Ba = 137g/mol

Mass of Ba from the balanced equation = 3 x 137 = 411g

Molar mass of Na = 23g/mol

Mass of Na from the balanced equation = 6 x 23 = 138g

Molar mass of Ba3(PO4)2 = (3 x 137) + 2[31 + (4x16)] = 411 + 2[31 + 64] = 601g/mol

Mass of Ba3(PO4)2 from the balanced equation = 1 x 601 = 601g

Summary:

From the balanced equation above,

411g of Ba reacted to produce 138g of Na and 601g of Ba3(PO4)2.

A. Determination of the mass of Na produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 138g of Na.

Therefore, 10g of Ba will react to produce = (10 x 138)/411 = 3.36g of Na.

Therefore, 3.36g of Na is produced.

B. Determination of the mass of Ba3(PO4)2 produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 601g of Ba3(PO4)2.

Therefore, 10g of Ba will react to produce = (10 x 601)/411 = 14.62g of Ba3(PO4)2.

Therefore, 14.62g of Ba3(PO4)2 is produced.

7 0
3 years ago
What is 17.8 + 12.115 in sig fig
iogann1982 [59]

Answer:

Explanation:

17.8 + 12.115 = 29.9

Sig Figs

3

29.9

Decimals

1

29.9

Scientific Notation

2.99 × 10 1

E-Notation

2.99e+1

Words

twenty-nine point nine

4 0
3 years ago
How does the state of atoms in a neon light change when light is emitted?
Blababa [14]
The state of atoms in a neon light when light is emitted is loss of energy.
5 0
3 years ago
Read 2 more answers
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