We calculate the molar concentration [Cl⁻] using stoichiometry. MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.68 mol MnCl2/1L × 2 mol Cl⁻ / 1 mol MnCl2 = 1.4 M
The answer to this question is [Cl⁻] = 1.4 M
<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
The balanced equilibrium reaction for the ionization of calcium fluoride follows:
s 2s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ca^{2+}][F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BF%5E-%5D%5E2)
We are given:
Putting values in above equation, we get:
To calculate the solubility in g/L, we will multiply the calculated solubility with the molar mass of calcium fluoride:
Molar mass of calcium fluoride = 78 g/mol
Multiplying the solubility product, we get:
Hence, the correct answer is Option b.
Answer:
two atoms both non metals
Explanation:
because if the bond is formed between atoms with similar electronegativity since covalent bonding is the sharing of electrons
Answer:
The initial temperature is 499 K
Explanation:
Step 1: Data given
initial volume = 12 cm3 = 12 mL
Final volume = 7 cm3 = 7mL
The final temperature = 18 °C = 291 K
Step 2: Calculate the initial temperature
V1/T1 = V2/T2
⇒with V1 = the initial volume = 0.012 L
⇒with T1 = the initial volume = ?
⇒with V2 = the final volume 0.007 L
⇒with T2 = The final temperature = 291 K
0.012 / T1 = 0.007 / 291
0.012/T1 = 2.4055*10^-5
T1 = 0.012/2.4055*10^-5
T1 = 499 K
The initial temperature is 499 K
To measure the kinetic engery from the inside and outside of something to be able to tell how hot or coll something is.. without touching it also
