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cupoosta [38]
4 years ago
5

Draw the addition products formed when one equivalent of HBr reacts with 2,4-hexadiene. (Draw a single product for each. Ignore

stereochemical or chiral isomers.)

Chemistry
1 answer:
Tems11 [23]4 years ago
7 0

Answer:

The products are 4-bromo-2-hexene and 2-bromo-3-hexene

Explanation:

The reaction starts between terminal carbon of of of the double bonds and H^{+}. After attaching H^{+} to the carbon, one double bond disapears leaveing nearby CH positively charged. This intermediate is a resonance hybrid of two possible structures. Reaction of bromide at one of the carbons gives the 1,2-addition product and at the other carbon gives 1,4-addition product.

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