Question

Draw the addition products formed when one equivalent of HBr reacts with 2,4-hexadiene. (Draw a single product for each. Ignore stereochemical or chiral isomers.)

Answer 1

Answer:

The products are 4-bromo-2-hexene and 2-bromo-3-hexene

Explanation:

The reaction starts between terminal carbon of of of the double bonds and $H^{+}$. After attaching $H^{+}$ to the carbon, one double bond disapears leaveing nearby CH positively charged. This intermediate is a resonance hybrid of two possible structures. Reaction of bromide at one of the carbons gives the 1,2-addition product and at the other carbon gives 1,4-addition product.