Answer:
a modular router
Explanation:
A modular router is a type of router that will provide multiple slots, this will enable the network engineer to either change or increase the number of space the router has.
A layer 3 switch cannot provide a WAN connectivity even though it can increase the number of ports on a router. The concept of PoE capability of any device have nothing to do with the number of ports it has. If the Engineer decides to use another fixed configuration router it will still lead to the same problem in the future because it cannot guarantee or provide the flexibility of future growth adaptation which can be given by a modular router if put in use.
Answer:
nutcracker and can opener
Explanation:
Answer:
I1 to K2: Use a formula to link the cells. Create a formula in column L that calculates the averages for each matching category in K2:
<h3>hope it's help you </h3><h3>plz mark as brain list </h3>
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}
All of the above. If that’s not an option if it’s multiple choice let me know. Everyone uses web browser/the internet no matter the career.