Answer:
The reflected resistance in the primary winding is 6250 Ω
Explanation:
Given;
number of turns in the primary winding, = 50 turns
number of turns in the secondary winding, = 10 turns
the secondary load resistance, = 250 Ω
Determine the turns ratio;
Now, determine the reflected resistance in the primary winding;
Therefore, the reflected resistance in the primary winding is 6250 Ω
Answer: 2940 J
Explanation: solution attached:
PE= mgh
Substitute the values:
PE= 10kg x 9.8 m/s² x 30 m
= 2940 J
Answer: Leandra puts on her mittens because if you do not you will burn your self, due to extremely high temperatures.
Explanation:
According to the statements the number of electrons is 150, then
e = 150
But there is a positive charge of +22e, then the number of protons would be
p = 150+172
If the mass of the electrons is
And the mass of the protong is
We have that the total mass of the system would be
The second option rolling friction