The electrons of photosystem ii are excited and transferred to electron carriers. From which molecule or structure do the photos
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Answer:
(a). The speed at the moment of being thrown is 30.41 m/s.
(b). The maximum height is 47.18 m.
Explanation:
Given that,
Weight of stone = 3.00 N
Height = 15 m
Speed = 25.0 m/s
(a). We need to calculate the speed at the moment of being thrown
Using work energy theorem
Put the value into the formula
(b). We need to calculate the maximum height
Using work energy theorem
Here, =0
Put the value into the formula
Hence, (a). The speed at the moment of being thrown is 30.41 m/s.
(b). The maximum height is 47.18 m.
The change in the player's internal energy is -491.6 kJ. The number of nutritional calories is -117.44 kCal
For this process to take place, some of the basketball player's perspiration must escape from the skin. This is because sweating relies on a physical phenomenon known as the heat of vaporization.
The heat of vaporization refers to the amount of heat required to convert 1g of a liquid into a vapor without causing the liquid's temperature to increase.
From the given information,
- the work done on the basketball is dW = 2.43 × 10⁵ J
The amount of heat loss is represented by dQ.
where;
- dQ = -mL
∴
Using the first law of thermodynamics:b
dU = dQ - dW
dU = -mL - dW
dU = -(0.110 kg × 2.26 × 10⁶ J/kg - 2.43 × 10⁵ J)
dU = -491.6 × 10³ J
dU = -491.6 kJ
The number of nutritional calories the player has converted to work and heat can be determined by using the relation:
dU = -117.44 kcal
Learn more about first law of thermodynamics here: