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sashaice [31]
2 years ago
14

I propose to design a new drug which will act as an inhibitor for an enzyme. If I have used all current information about the me

chanism of this enzyme to design this inhibitor and I carefully engineer it with similar chemical properties of the transition state, what type of inhibitor am I attempting to engineer and how will I know if I have succeeded?
a. An uncompetitive inhibitor, collect kinetic data both in the presence and absence of inhibitor and watch for a change in Vmax b. A competitive inhibitor, collect kinetic data both in the presence and absence of inhibitor and watch for a change in Vmax c. An uncompetitive inhibitor, collect kinetic data both in the presence and absence of inhibitor and watch for a change in Km d. A competitive inhibitor, collect kinetic data both in the presence and absence of inhibitor and watch for a change in Km
Chemistry
1 answer:
lilavasa [31]2 years ago
6 0

Answer:

d. A competitive inhibitor, collect kinetic daa both in the presence and absence of inhibitor and watch for a change in Km.

Explanation:

According to the description, the inhibitor was designed in a way when it binds the enzyme, the transition state achieved will be close to the one observed when the substrate binds.

In other words, the aim was to design an inhibitor that will bind the free enzyme in a reversible way, competing with the substrate for the binding sites.

As the inhibitor will be binding the same site as the substrate, the apparent affinity of the enzyme for the substrate will decrease. And the higher the affinity of the inhibitor for the enzyme, stronger the effect it will have over the affinity of the enzyme for the substrate.

Quantitatively speaking, the apparent Km of the enzyme for the substrate will increase with the inhibitor concentration, as the affinity of the enzyme for the substrate decreases.

In summary, what is being engineered is a competitive inhibitor, and the way of knowing if the design was successful, is collecting kinetic data in presence and absence of inhibitor, and watch for changes in the apparent Km.

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The atomic symbol Superscript 206 subscript 82 upper P b. represents lead-206 (Pb-206), an isotope that has 82 protons and 124 n
Serggg [28]

Answer:

\left \{ {{y=206} \atop {x=82}}Pb \right.

Explanation:

isotopes are various forms of same elements with different atomic number but different mass number.

Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are

  • Alpha particle emission  \left \{ {{y=4} \atop {x=2}}He \right.
  • Beta particle emission    \left \{ {{y=0} \atop {x=-1}}e \right.
  • gamma radiation             \left \{ {{y=0} \atop {x=0}}γ \right.

in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.

Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below

\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right +  \left \{ {{y=0} \atop {x=0}}γ\right.

Thus the atomic symbol is \left \{ {{y=206} \atop {x=82}}Pb\right

8 0
3 years ago
Read 2 more answers
How many moles of potassium hydroxide are needed to completely react with 2.94 moles of aluminum sulfate
ArbitrLikvidat [17]

Answer:- Third choice is correct, 17.6 moles


Solution:- The given balanced equation is:


Al_2(SO_4)_3+6KOH\rightarrow 2Al(OH)_3+3K_2SO_4


We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.


From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.


It is a simple mole to mole conversion problem. We solve it using dimensional set up as:


2.94molAl_2(SO_4)_3(\frac{6molKOH}{1molAl_2(SO_4)_3})


= 17.6 mol KOH


So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.



6 0
3 years ago
What particle decay is this? 210 83 Bi→210 84 Po ​
sesenic [268]

Answer:

Beta emission

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When a nucleus undergoes beta emission, the mass number of the parent and daughter nuclei remain the same while the atomic number of the daughter nucleus is greater than that of its parent by one unit.

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2 years ago
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Hatshy [7]

Answer:

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given the specific heat of water as 1 cal/g·°C. Substitute the known values into heat = mcΔT and solve for amount of heat:

=  heat=(75.0 g)(1 cal/ g· °C )(35.0°C) =

= 75x1x35=2625 cal

6 0
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