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butalik [34]
3 years ago
12

Suppose 7 pints of a 23​% alcohol solution is mixed with 3 pints of a 70​% alcohol solution. what is the concentration of alcoho

l in the new 10​-pint ​mixture?
Chemistry
1 answer:
vichka [17]3 years ago
8 0
7*0.23 =1.61 pints of alcohol in 7 pints of 23% solution
3*0.7 =2.1 pints of alcohol in 3 pints of 70% solution
10x = pints pf alcohol in 10-pint mixture

7*0.23+3*0.7=10x
1.61+2.1=10x
3.71 = 10x
x = 0.371 = 37.1% is the concentration of the new 10-pint mixture

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what is the trend for the size as you go from Be to Mg to Ca? does the atomic size increase, decrease, or remain the same? how w
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Answer:

the size of Ca is the greatest ,then Mg is the greater on size than Be

Explanation:

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see that all the elements are in the same group but are in different period

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Which or these equations is balanced H2SO4 + 2Al &gt; Al2(SO4)3 + H2 or 2KCl + Pb(NO3)2 &gt; 2KNO3 + PbCl2
Dmitry_Shevchenko [17]

Balancing of chemical equation is essential because of the law of conservation of mass, which states that the mass of a system can not be created or removed.

The second equation is balanced

2KCl_(_a_q_) +Pb(NO_3)_2_(_a_q_) ==> 2KNO_3_(-a_q_) + PbCl_2(_a_q_)

This is because the number of elements of each atom in the product side equal the number of elements of each atom on the reactant side.

The first equation is not balanced

H_2SO_4 _(_a_q) + 2Al_(_s_) ==> Al(SO_4)_3_(_a_q_) + H_2_(_g_)

This is because there is 1 molecule of SO_4^{-2} on reactant side as compared to 3 molecules of SO_4^{-2}

To balance the equation we add a coefficient of 3 on sulphuric acid (H_2SO_4) and a coefficient of 3 on hydrogen (H_2)

3H_2SO_4_(_a_q_) + 2Al_(_s_) ==> Al(SO_4)_3_(_a_q_) + 3H_2_(_g_)

7 0
4 years ago
The rotten smell of a decaying animal carcass is partially due to a nitrogen-containing compound called putrescine. Elemental an
gtnhenbr [62]

Answer:C2H6N

Explanation:

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H = 13.73g/1 = 13.73moles

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Divide through with the smallest moles value.

C= 4.541/2.269 = 2

H= 13.73/2.269=6

N= 2.269/2.269=1

Therefore the empirical formula is

C2H6N

8 0
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