Explanation:
A mixture in which there is uniform distribution of solute particles into the solvent is known as a homogeneous mixture.
For example, sugar dissolved in water is a homogeneous mixture.
On the other hand, a mixture in which there is uneven distribution of solute particles into the solvent is known as a heterogeneous mixture.
For example, sand present in water is a heterogeneous mixture.
Comment on given situations will be as follows.
(a) Air in a closed bottle - It is a homogeneous mixture because there will be even distribution of other gases that are present in air.
(b) Air over New York City - It is a heterogeneous mixture because there will be presence of some dust particles, fog or smoke into the air. Distribution of all these particles will be uneven. This will make air over New York City heterogeneous in nature.
Answer:

Explanation:
In this case, we have to start with the <u>chemical reaction</u>:

So, if we start with <u>10 mol of cyclohexanol</u> (
) we will obtain 10 mol of cyclohexanol (
). So, we can calculate the grams of cyclohexanol if we<u> calculate the molar mass:</u>

With this value we can calculate the grams:

Now, we have as a product 500 mL of
. If we use the <u>density value</u> (0.811 g/mL). We can calculate the grams of product:

Finally, with these values we can calculate the <u>yield</u>:
%= (405.5/820)*100 = 49.45 %
See figure 1
I hope it helps!
<u>Answer:</u> The number of phosphorus atoms in given amount of copper(II) phosphate is 
<u>Explanation:</u>
We are given:
Moles of copper(II) phosphate
= 7.00 mol
1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms
Moles of phosphorus in copper(II) phosphate = 
According to the mole concept:
1 mole of a compound contains
number of particles
So, 7.00 moles of copper(II) phosphate will contain =
number of phosphorus atoms.
Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is 
Answer : The mass of
added must be, 61.9 grams
Explanation : Given,
Mass of
= 40 g
Molar mass of
= 105.9 g/mol
First we have to calculate the moles of
.

Now we have to calculate the moles of 
The balance chemical reaction will be:

From the balanced reaction we conclude that
As, 1 mole of
react with 1 mole of 
So, 0.378 mole of
react with 0.378 mole of 
Now we have to calculate the mass of 

Molar mass of
= 164 g/mol

Thus, the mass of
added must be, 61.9 grams