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Savatey [412]
3 years ago
14

a mass of 1.00 kg of water at temperature T is poured from a height of 0.100 km into a vessel containing water of the same tempe

rature T, and a temperature change of 0.100 is measured. What mass of water was in the vessel? ignore heat flow into the vessel, the thermometer etc.
Physics
1 answer:
Mariana [72]3 years ago
6 0

Answer:

1.34352 kg

Explanation:

m_w = Mass of water falling = 1 kg

h = Height of fall = 0.1 km

\Delta T = Change in temperature = 0.1

c = Specific heat of water = 4186 J/kg K

g = Acceleration due to gravity = 9.81 m/s²

m_v = Mass of water in the vessel

Here the potential energy will balance the internal energy

m_wgh=m_wc\Delta T+m_vc\Delta T\\\Rightarrow m_v=\dfrac{m_wgh-m_wc\Delta T}{c\Delta T}\\\Rightarrow m_v=\dfrac{m_wgh}{c\Delta T}-m_w\\\Rightarrow m_v=\dfrac{1\times 9.81\times 100}{4186\times 0.1}-1\\\Rightarrow m_v=1.34352\ kg

Mass of the water in the vessel is 1.34352 kg

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aleksley [76]

Magnitude of normal force acting on the block is 7 N

Explanation:

10N = 1.02kg

Mass of the block = m = 1.02 kg

Angle of incline Θ =  30°

Normal force acting on the block = N

From the free body diagram,

N = mgCos Θ

N = (1.02)(9.81)Cos(30)

N = 8.66 N

Rounding off to nearest whole number,

N = 7 N

Magnitude of normal force acting on the block = 7 N

7 0
2 years ago
Consider the interactions involved when you use a TV remote control to change the channel. Classify each interaction as long ran
makvit [3.9K]

Explanation:

Following are two interactions that are generally involved when we use a TV remote control to change the channel :

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2. Now remote sends signal to Television, this is a long range interaction.

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2 years ago
A comet is in an elliptical orbit around the sun. its closest approach to the sun is a distance of 4.5 1010 m (inside the orbit
barxatty [35]

r1 = 5*10^10 m , r2 = 6*10^12 m

v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

M is mass of sun = 1.98*10^30 kg

G = 6.67*10^-11 N.m^2/kg^2

0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

v2 = 5.35*10^4 m/s

4 0
3 years ago
At what point in the swing of the pendulum is the potential energy completely converted into Kinetic energy
artcher [175]
Point a because point a is the highest at potential energy converting into the highest kinetic energy.
4 0
2 years ago
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Equations to use: v= λ ∙ f v=d/t
Margarita [4]

b. 460.8 m/s

Explanation:

The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is

f=\frac{v}{2L}

where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:

v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s

c. 18,000 m

Explanation:

The relationship between speed of the wave, distance travelled and time taken is

v=\frac{d}{t}

where

v = 6,000 m/s is the speed of the wave

d = ? is the distance travelled

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Re-arranging the formula and substituting the numbers into it, we find:

d=vt=(6,000 m/s)(3 s)=18,000 m

3 0
3 years ago
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